Answer: -
Osmosis is the process by which water molecules move from a region of high solvent concentration to low solvent concentration.
Now in any solution there are just solute and solvent.
If the amount of solvent is more in a solution then the amount of solute would be less.
Again if the amount of solvent is less in a solution then amount of solute is more.
Thus we can write that :- osmosis is the movement of water molecules from a region of low solute concentration to high solute concentration.
D.
A more accurate answer would be -50 m/s. 50 m/s is the change in speed.
Answer:
D 4P +3O₂ → 2 P₂O₃
Explanation:
In this problem, we need to convert the mass of phosphorus and oxygen to moles trying to find the ratio of reaction (The moles of P that reacts per mole of O₂):
<em>Moles P:</em>
12.4g P * (1mol P / 31g) = 0.4 moles
<em>Moles O₂:</em>
9.6g * (1mol / 32g) = 0.3 moles
The ratio of reaction is:
0.4 mol / 0.3 mol = 1.33 = 4 moles of P / 3 moles of O₂
That means 4 moles of P react with 3 moles of O₂ and the reaction that represents this ratio is:
<h3>D 4P +3O₂ → 2 P₂O₃</h3>
Answer:
magnesium metal
Explanation:
According to the redox reaction equation, six electrons were transferred hence n=6 and F= Faraday's constant 96500C. ∆G° is given hence E°cell can easily be calculated as follows:
From ∆G°= -nFE°cell
E°cell= -∆G°/nF= -(-411×10^3/96500×6)
E°cell= 0.7098V
But for Al3+(aq)/Al(s) half cell, E°= -1.66V from standard table of reduction potentials.
E°cell= E°cathode- E°anode but Al3+(aq)/Al(s) half cell is the cathode
Hence
E°anode=E°cathode - E°cell
E°anode= -1.66-0.7098= -2.37V
This is the reduction potential of Mg hence the anode material was magnesium metal
Answer:
See explanation
Explanation:
When we look at SO3 we will notice that the compound is trigonal planar and it is symmetric. This means that it has equal charge distribution hence its dipoles cancel out resulting in a zero net dipole moment.
However, COH2 is also trigonal planar but is non-symmetric. Hence, its dipole moments do not cancel out, hence the molecule has a resultant dipole moment and is a polar molecule
