A sample of kerosene has a mass of 36.4g. It’s volume is 45.6mL. What is the density of kerosene?
1 answer:
Answer:
<h2>Density = 0.8 g/cm³</h2>Explanation:
The density of an object can be found using the formula
<h3>From the question
mass of kerosene = 36.4 g
volume of kerosene = 45.6 mL
To find the density substitute the values into the above formula and solve
We have
<h3>= 0.7982
We have the final answer as
<h3>Density = 0.8 g/cm³</h3>Hope this helps you
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Answer : The correct answer for change in freezing point = 1.69 ° C
Freezing point depression :
It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .
SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .
It can be expressed as :
ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m
Where : ΔTf = change in freezing point (°C)
i = Von't Hoff factor
kf =molal freezing point depression constant of solvent.
m = molality of solute (m or )
Given : kf = 1.86
m = 0.907 )
Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1
Plugging value in expression :
ΔTf = 1* 1.86 * 0.907
)
ΔTf = 1.69 ° C
Hence change in freezing point = 1.69 °C