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PSYCHO15rus [73]
4 years ago
7

Is there an atom within an atom?

Physics
1 answer:
Anvisha [2.4K]4 years ago
6 0

No. An atom is made up of 3 kinds of particles, protons, neutrons, and electrons. Protons and neutrons make up the center of the atom.

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BRAINLIEST HERE COME GET IT
vitfil [10]
Oh that would be lovely! Thank you!
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You are climbing in the high sierra when you suddenly find yourself at the edge of a fog-shrouded cliff. to find the height of t
sergey [27]
The total time it takes the sound to reach our on top of the cliff (10.0 s) is actually sum of two times:
- the time it takes the rock to hit the ground starting from the top of the cliff, t1
- the time it takes the sound to reach the top of the cliff starting from the ground, t2
1) The rock moves by uniformly accelerated motion, with constant acceleration g=9.81 m/s^2. Its law of motion is given by y(t)=h-v_0t-\frac{1}{2}gt^2, where v_0=0 is the initial velocity of the rock, and h is the height of the cliff. The time t1 is the time at which the rock reaches the ground, so that y(t1)=0, and the equation becomes
0=h-\frac{1}{2}gt_1^2
2) The sound moves from the ground to the top of the cliff by uniform motion, with constant speed v=343 m/s. Therefore, the sound covers the distance h (the height of the cliff) in a time t2 given by
h=vt_2
3) If we rewrite h in both equations, we can write:
=\frac{1}{2}gt_1^2=vt_2 (1)
4) We also know that the sum of t1 and t2 is equal to 10 seconds:
t_1+t_2=10
from which we find
t_2=10-t_1
if we substitute this into eq.(1), we get
\frac{1}{2}gt_1^2+vt_1-10v=0
Numerically:
4.9t_1^2 + 343 t_1 - 3430=0
Solving the equation, we find the solution t_1=8.87 s (the other solution is negative, so it does not have physical meaning). As a consequence,
t_2 = 10-t_1 = 1.13 s
and the height of the cliff is given by
<span>h=vt_2=(343 m/s)(1.13 s)=388 m</span>
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The frequency of the radio wave is:
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where c is the speed of light and f the frequency. Plugging numbers into the equation, we find
\lambda= \frac{3 \cdot 10^8 m/s}{102.1 \cdot 10^6 Hz}= 2.94 m
and this is the wavelength of the radio waves in the problem.
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