Its true...water takes the shape of its container and it flows..please give me 5 stars and brainliest
How much gravitational potential energy does the block have
when it gets to the top of the ramp ?
(weight) x (height) = (15 N) x (0.2 m) = 3 Joules .
If there were no friction, you would only need to do 3 Joules of work
to lift the block from the bottom to the top.
But the question says you actually have to do 4 Joules of work
to get the job done.
Friction stole one of your Joules along the way.
Choice-4 is not the correct one.
Choice-1 is the correct one.
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Notice that the mass of the block is NOT 15 kg , and you
don't have to worry about gravity to answer this question.
The formula for potential energy is (m)·(g)·(h) .
But (m·g) is just the WEIGHT, and the formula
is actually (weight)·(height).
The question GIVES us the weight of the block . . . 15 N .
So the potential energy at the top is just (15N)·(0.2m) = 3 Joules.
Newton's second law is stated as:
F=ma,
a = (7-4)/1.5 = 2 m/s^2 (it is a deceleration due to impact with floor. And thus the ball exerts force on the floor).
Therefore,
F= 0.3*2 = 0.6 N
Answer:
Explanation:
Angular speed of the motion ( SHM )
ω = √k/m
= √(580/.23 )
= 50.20 radian /s
a ) Rate of doing work
= power = force x velocity
At the equilibrium position force becomes zero so
rate of doing work is zero.
b )
If a be the amplitude
1/2 k a² = 170
a = .7655 m
kinetic energy at equilibrium = 1/ 2 m v₀²
1/ 2 m v₀² = 170
.5 x 23 v₀² = 170
v₀ = 3.84 m /s which is the maximum velocity.
Given x = .66 where rate of doing work is to be calculated.
Force at x = ω² x
= 50.20² x .66 =
= 1663.22 N
Velocity v = v₀ √( a² - x² )
= 3.84 √( .7655² - .66 )
= 3.84 x .387
= 1.486 m/s
power = force x velocity
= 1663.22 x 1.486
= 2471.55 W .
