Use the given data to calculate the total mass of hydrogen available for fusion over the lifetime of the sun.

1 answer:

8 0

Total mass of the Sun = 2x10^30kg

So 76% of that = (2x10^30kg)*(0.76) = 1.52x10^30kg ----> total amount of Hydrogen if only 12% of that is used for fusion, then (1.52x10^30kg)*(0.12) = 1.82x10^9kg

You might be interested in

A car’s momentum is p when it is traveling with a velocity of v. If the velocity of that car doubles, what is the new momentum o

lubasha [3.4K]

Answer:

∆p=(m2v)kg.m/s

Explanation:

∆p=mv where v=2v. hence ∆p=m2v

5 0

3 years ago

Read 2 more answers

How does the sun affect the water cycle?

Savatey [412]

i think the answer is D.

heating surface water causes it to evaporate and enter the air as a gas.

4 0

3 years ago

Read 2 more answers

The parallax method of measuring star distances gives most accurate results when the gap between two observations of a star is a

EleoNora [17]

b. It ensures that measurements are taken from two points
that are very far apart.

Measurements taken six months apart are the farthest apart
that an astronomer can ever get ... they're on opposite sides
of the Earth's orbit !

8 0

3 years ago

Read 2 more answers

A smith needs to melt 0.0500 kg of gold at 21.0°C. How much heat must be added? (Remember, she has to heat it to the melting poi

baherus [9]

Answer:

9704.6 J

Explanation:

Total Thermal Energy

= Energy required to bring gold to melting point + Energy required to change the state of gold from solid to liquid

= mcT + mlf [bolded is energy used to bring gold to melting point, italicised is state change of gold from sold to liquid]

= (0.0500)(126)(1063 - 21) + (0.0500)(6.28 × 10^4)

= 9704.6 J

4 0

3 years ago

Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth if the force on

Sati [7]

Since you already gave us the weight of the 2.5-kg box,
we don't even need to know what the distance is, just
as long as it doesn't change.

Look at the formula for the gravitational force:

F = G m₁ m₂ / R² .

If 'G', 'm₁' (mass of the Earth), and 'R' (distance from the Earth's center)
don't change, then the Force is proportional to m₂ ... mass of the box,
and you can write a simple proportion:

(6.1 N) / (2.5 kg) = (F) / (1 kg)

Cross-multiply: (6.1 N) (1 kg) = (F) (2.5 kg)

Divide each side by (2.5 kg): F = (6.1N) x (1 kg) / (2.5 kg) = 2.44 N .

5 0

3 years ago