Answer:
hello some data related to your question is missing attached below is the missing data
answer : 63700 Ib/hr
Explanation:
Given data :
Limestone mix : consists of 94% CaCO3 and 6% inert material
Actual feed rate = 36,000 Ib/hr
SO2 in flue gas = 20,314 Ib/hr
FGD efficiency = 97%
resulting sludge contains 58% solids
<u>Calculate the Total sludge production rate </u>
First : determine SO2 removed in sludge
= 0.97 * 20314
= 19704.58 Ib/hr
next : moles of SO2 removed
= 19704.58 / 64 Ib/ Ib mol
= 307.88 Ib mol / hr
also moles of CaSO3 produced = 307.88 Ib mol / hr
mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr
Therefore Total sludge production rate
= 36946.09 / 0.58
= 63700.15 Ib/hr
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Water vapor and carbon dioxide!
Answer:
Explanation:
Work, U, is equal to the force times the distance:
U = F · r
Force needed to lift the weight, is equal to the weight: F = W = m · g
so:
U = m · g · r
= 20.4kg · 9.81 
· 1.50m
= 35.316 
= 35.316 W
