Question

WILL MARK BRAINLIEST! How many liters of 4.0 M NaOH solution will react with 0.60 liters 3.0 M H2SO4?

Answer 1

Mol h2so4=0,6x3=1,8mol

MolOH-=Mol H+=2molh2so4=1,8x2=3,6mol

=> Mol NaOH=3,6mol=>V naoh= 3,6:4=0,9liters.

So, A is the correct answer

Answer 2

Answer: The correct answer is Option A.

Explanation:

To calculate the volume of NaOH, we use the equation used for the neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ = n-factor, molarity and volume of acid which is sulfuric acid.

$n_2,M_2\text{ and }V_2$ = n-factor, molarity and volume of base which is sodium hydroxide.

We are given:

$n_1=2\\M_1=3M\\V_1=0.60L\\n_2=1\\M_2=4.0M\\V_2=?L$

Putting values in above equation, we get:

$2\times 3\times 0.6=1\times 4\times V_2\\\\V_2=0.9L$

Hence, the correct answer is Option A.