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Kazeer [188]
3 years ago
5

WILL MARK BRAINLIEST! How many liters of 4.0 M NaOH solution will react with 0.60 liters 3.0 M H2SO4?

Chemistry
2 answers:
frutty [35]3 years ago
8 0

Mol h2so4=0,6x3=1,8mol

MolOH-=Mol H+=2molh2so4=1,8x2=3,6mol

=> Mol NaOH=3,6mol=>V naoh= 3,6:4=0,9liters.

So, A is the correct answer

11Alexandr11 [23.1K]3 years ago
3 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

To calculate the volume of NaOH, we use the equation used for the neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 = n-factor, molarity and volume of acid which is sulfuric acid.

n_2,M_2\text{ and }V_2 = n-factor, molarity and volume of base which is sodium hydroxide.

We are given:

n_1=2\\M_1=3M\\V_1=0.60L\\n_2=1\\M_2=4.0M\\V_2=?L

Putting values in above equation, we get:

2\times 3\times 0.6=1\times 4\times V_2\\\\V_2=0.9L

Hence, the correct answer is Option A.

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vitfil [10]

Answer:

<h3>Theanswer is 6 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

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We have the final answer as

<h3>6 moles</h3>

Hope this helps you

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