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Feliz [49]
3 years ago
5

You are exploring a planet and drop a small rock from the edge of a cliff. In coordinates where the +y direction is downward and

neglecting air resistance, the vertical displacement of an object released from rest is given by y − y0 = 1 2 gplanett2, where gplanet is the acceleration due to gravity on the planet. You measure t in seconds for several values of y − y0 in meters and plot your data with t2 on the vertical axis and y − y0 on the horizontal axis. Your data is fit closely by a straight line that has slope 0.400 s2/m. Based on your data, what is the value of gplanet?
Physics
1 answer:
Lelu [443]3 years ago
6 0

Answer:

value of the acceleration of gravity on the planet is 5.00 m/s²

Explanation:

The problem is similar to a free fall exercise, with another gravity value, the expression they give us is the following:

       y-yo = ½ gₐ t²       (1)

They tell us that they make a squared time graph with the variation of the distance, it is appropriate to clarify this in a method to linearize a curve, which is plotted the nonlinear axis to the power that is raised, specifically, the linearization of a curve The square is plotted against the other variable.

  Let's continue our analysis, as we have a linear equation, write the equation of the line.

     

        y1 = m x1 + b       (2)

where  “y1” the dependent variable, “x1” the independent variable, “m” the slope and “b” the short point

In this case as the stone is released its initial velocity is zero which implies that b = 0,

We plot on the “y” axis the time squared “t²” and on the horizontal axis we place “y-yo”.  To better see the relationship we rewrite equation 1 with this form

        t² = 2 /gₐ  (y-yo)

 

With the two expressions written in the same way, let's relate the terms one by one

        y1 = t²

        x1 = (y-yo)

        m = 2/gap

        b= 0

We substitute and calculate

        m = 2/gp

        gₐ = 2/m

        gₐ = 2/ 0.400

        gₐ = 5.00 m / s²

This is the value of the acceleration of gravity on the planet, note that the decimals are to keep the figures significant

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siniylev [52]

Answer:

The size (diameter) of the basketball's shadow on the wall is approximately 53.38 cm

Explanation:

The given parameters of the basketball are;

The diameter of the basketball = 23 cm (9 inches)

The distance of the light bulb from the closest side of the basketball = 3 m

The distance from the ball to the wall = 4 m

The distance from the light source to the center of the ball, d = 3 m + 0.23/2 m = 3.115 m

The angle the light ray makes with the edge of the ball, θ = arctan(0.115/3.115)

Therefore, the ratio of the shadow width divided by 2 to the distance from the light from the wall = 0.115/3.115

The distance from the light from the wall = 3 m + 4 m + 0.23 m = 7.23 m

Therefore;

((The width of the shadow)/2)/(The distance from the light from the wall) = 0.115/3.115

∴ ((The width of the shadow)/2)/(7.23 m) = 0.115/3.115

((The width of the shadow)/2) = 7.23 m × 0.115/3.115 = 16629/62300 m ≈ 0.2669 m = 26.69 cm

The width (diameter) of the shadow on the wall = 2 × 16629/62300 m ≈ 0.5338 m = 53.38 cm

The size (diameter) of the basketball's shadow on the wall ≈ 53.38 cm

4 0
2 years ago
A tank contains one mole of carbon dioxide gas at a pressure of 6.70 atm and a temperature of 23.0°C. The tank (which has a fixe
quester [9]

Answer: 888.45 K or 615.3 °c

Explanation:

According to Gay Lussacs law which states that at constant volume, pressure of an ideal gas is directly proportional to it's absolute temperature.

P/T = Constant

Therefore, P1/T1 = P2/T2

P1 = 6.7 atm

T1= 23°c = 273.15 + 23 = 296.15K

Since P2 is tripled, then,

P2 = 6.7 x 3= 20.1 atm

T2 = (20.1 x 296.15) ÷ 6.7

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3 years ago
What is the kinetic energy of a 55 kilogram skier traveling at meters per second
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How many meters per second was it traveling
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A bat can detect small objects such as an insect whose size is approximately equal to the wavelength of the sound the bat makes.
slamgirl [31]

Answer:

size of insect = wavelength = 16.1 mm

Explanation:

Since the bat can detect the size of small insects which are of size equal to the wavelength of sound in air

So here we can say that the wavelength of sound is the ratio of speed of sound and its frequency

here we know that

speed of sound in air is 536 m/s

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7 0
3 years ago
Two forces whose resultant is 100N are at right angle to eachother. if one of them makes an angle of 30° with the resultant, det
mihalych1998 [28]

Let <em>F₁ </em>and <em>F₂</em> denote the two forces, and <em>R</em> the resultant force.

<em>F₁ </em>and <em>F₂</em> point perpendicularly to one another, so their dot product is

<em>F₁ </em>• <em>F₂</em> = 0

<em />

We're given that one of these vectors, say <em>F₁</em>, makes an angle with <em>R</em> of 30°, so that

<em>F₁</em> • <em>R</em> = ||<em>F₁</em>|| ||<em>R</em>|| cos(30°)

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So, knowing that ||<em>R</em>|| = 100 N, we get that

(100 N) ||<em>F₁</em>|| cos(30°) = ||<em>F₁</em>||²

(100 N) cos(30°) = ||<em>F₁</em>||

||<em>F₁</em>|| ≈ 86.6 N

(And the same would be true for <em>F₂</em>.)

8 0
2 years ago
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