Question

Calculate the rate of some reaction that obeys Avrami kinetics, assuming that the constants n and k have values of 2.0 and 0.006, respectively, for time expressed in seconds.

Answer 1

Answer:

rate=0.093 s⁻¹

Explanation:

Given Data

n=2.0

k=0.006

assume y=0.5 because it is not given in question

rate=?

Solution

As we know that

$e^{-kt^{n} } =1-y\\t^{n}=-\frac{ln(1-y)}{k}\\ t=-(\frac{ln(1-y)}{k} )^{\frac{1}{n} }\\ t=-(\frac{ln(1-0.5)}{0.006} )^{\frac{1}{2} }\\t=10.74 seconds\\rate=\frac{1}{t}\\ rate=\frac{1}{10.74} \\rate=0.093s^{-1}$