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Ksivusya [100]
2 years ago
15

Which of the following represents the ground state electron configuration for the Mn3+ ion? (Atomic number Mn = 25) 1s2 2s22p6 3

s23p63d4
Chemistry
2 answers:
V125BC [204]2 years ago
8 0

Answer:

1s^22s^22p^63s^23p^63d^{4}

Explanation:

Manganese is the element of group 7 and forth period. The atomic number of Manganese is 25 and the symbol of the element is Mn.

The electronic configuration of the element, manganese is -  

1s^22s^22p^63s^23p^63d^{5}4s^2

To form Mn^{3+}, it will lose 3 electrons from the valence electrons and thus the configuration of the ion is:-

1s^22s^22p^63s^23p^63d^{4}

Oksanka [162]2 years ago
4 0

Answer:

1s2 2s22p6 3s23p63d4

Explanation:

A total of 22 electrons  which is right for Mn3+  as At No. of Mn is 25.

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Answer : The volume of hydrogen gas at STP is 4550 L.

Explanation :

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The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

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V_1 = initial volume of gas = 50.0 L

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T_2 = final temperature of gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{100.0atm\times 50.0L}{300K}=\frac{1atm\times V_2}{273K}

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