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3 years ago

What do viceroy butterflies use to look like poisonous Monarch butterflies?

Chemistry

2 answers:

VMariaS [17]3 years ago

6 0

<h2>Answer:BRAINLIEST PLS</h2>

They use something called Mullerian mimic so they will be protected from predators

Explanation:

dimulka [17.4K]3 years ago

3 0

Monarch caterpillars consume milkweed plants and Viceroy caterpillars eat willows. You can tell the difference between the two now by their flight patterns. I would say the answer to your question is that though they are similar, Viceroy were the “uglier” for the simple reason of survival. Predators would find their coloration as un-tasty.

You might be interested in

Why is the wavelength of 633 nm used to analyze the standard solutions and drink samples?

RUDIKE [14]

Answer:

Corresponding with orange light, is the wavelength that blue solutions absorb the most.

Explanation:

If light is diffused through a solution of a given color, emerges of light from another wavelength is consumed and fades away. However, the wavelength of light relating to the color of such a solution is transferred. The color of the light is consumed is usually the contrasting one being transferred. As seen in a color wheel where, blue complement orange, red complement green, and yellow complement violet.

Thus, for a blue substance in solution, its complementary color is said to be orange, Given that the wavelength of orange color varies from 600 - 640 nm where it's maximum absorbance is approximately 633 nm. This wavelength is what is employed when analyzing the standard solutions and drink samples.

6 0

2 years ago

The irreversible elementary gas-phase reaction is carried out isothermally at 305 K in a packed-bed reactor with 100 kg of catal

tamaranim1 [39]

Answer:

0.856.

Explanation:

Lets represent the irreversible elementary gas phase equation of reaction as

A + B -----------------------------------> C + D

We have that the percentage of conversion is 80%.

The pressure, p from the ratio of exit pressure and entering pressure is p = 2/20 = 1/10 = 0.1.

Therefore, n = 1 - p^2/ weight of the catalyst = 1 - 0.1^2/ 100 = 9.9 × 10^-3 kg cat^-.

Now, let's make use of the equation below;

J/ 1 - J = kb^2/ u [ w - nw^2/2] ----------(1).

0.8 / 1- 0.8 = k ( 0.4)^2/ 10 [ 100 - (9.9× 10^-3 × 100^2/ 2] .

k = 4.95 dm^6/ kg.cat .mol.min

The turbulent flow= 1/2 × 9.9 × 10^-3 = 4.95 × 10^-3 kg cat^-.

Thus, making use of the equation (1) again, we have that;

{4.95 × 10^-3 × 0.4}/ 10 × [ 100 - (4.95 × 10^-3 × 100^2)] / 2 = 5.964.

Therefore, a/1 - a = 5.964.

5.964( 1 - a) = a.

5.964 - 5.964a = a.

5.964 = a + 5.964a.

5.964 = 6.964a.

a = 5.964/ 6.964 = 0.856.

5 0

2 years ago

What is one major difference between electromagnetic and mechanical waves?

djverab [1.8K]

While an electromagnetic wave is called just a disturbance, a mechanical wave is considered a periodic disturbance. Mechanical waves are also called elastic wavesas their propagation depends on the elastic properties of the medium through which the waves pass.

6 0

3 years ago

The vapor pressure of ethanol is 30°C at 98.5 mmHg and the heat of vaporization is 39.3 kJ/mol. Determine the normal boiling poi

Gelneren [198K]

Answer : The normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

Explanation :

The Clausius- Clapeyron equation is :

$\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = vapor pressure of ethanol at $30^oC$ = 98.5 mmHg

$P_2$ = vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg

$T_1$ = temperature of ethanol = $30^oC=273+30=303K$

$T_2$ = normal boiling point of ethanol = ?

$\Delta H_{vap}$ = heat of vaporization = 39.3 kJ/mole = 39300 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

$\ln (\frac{760mmHg}{98.5mmHg})=\frac{39300J/mole}{8.314J/K.mole}\times (\frac{1}{303K}-\frac{1}{T_2})$

$T_2=348.67K=348.67-273=75.67^oC$

Hence, the normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

3 0

3 years ago

Comparison between alkyl nucleophilic substitution with acyl nucleophilic substitution

S_A_V [24]

Answer:

in both nucleophil attach the c and leaving group leave but in acyl nu. subsituation c of carbonyl because of double bond with o have bigger positive charge and is better electrophil so do it faster,also alkyl nu. subsituation can have rearangment if going from sn1 and in sn2 sterichemistry of molecule change , acyl nu. subsituation most of time is better

4 0

3 years ago