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3 years ago

14

How many atoms of each element are in 4Na3PO4?

2 answers:

velikii [3]3 years ago

8 0

Answer:

12 sodium 4 phosphorus 16 oxygen. makes the table below to determine the number of atoms of each element in the chemical formula 4Ca(ClO3)2.

Elis [28]3 years ago

8 0

12 sodium 16 oxygen 4 phosphorus

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What does lower case k stand for?

DaniilM [7]

Just for more clarification, lowercase k is the rate constant. Uppercase K is the equilibrium constant. You can actually use k to find K (equilibrium constant). K=k/k' This means that the equilibrium constant is the rate constant of the forward reaction divided by the rate constant of the reverse reaction

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4 years ago

What is the volume of 64 g of oxygen gas 02 at STP

Yakvenalex [24]

Answer:

The volume would be 44.8 L

Explanation:

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4 years ago

A compound has a molar mass of 90. grams per mole and the empirical formula CH2O. What is the molecular formula of this compound

k0ka [10]

Answer:

C₃H₆O₃

Explanation:

Data:

EF = CH₂O

MM = 90. g/mol

Calculations:

EF Mass = (12.01 + 2.016 + 16.00) u = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

$n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{90. u}}{\text{30.03 u}} = 3.00 \approx 3$

MF = (CH₂O)₃ = C₃H₆O₃

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3 years ago

In an acid-base titration, a student uses 21.35 mL of 0.150 M NaOH to neutralize 25.00 mL of H2SO4. How many moles of acid are i

GalinKa [24]

Answer: There are 0.006 moles of acid in the flask.

Explanation:

Given: $V_{1}$ = 21.35 mL, $M_{1}$ = 0.150 M

$V_{2}$ = 25.0 mL, $M_{2}$ = ?

Formula used to calculate molarity of $H_{2}SO_{4}$ is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.15 M \times 21.35 mL = M_{2} \times 25.0 mL\\M_{2} = 0.1281 M$

As molarity is the number of moles of a substance present in a liter of solution.

Total volume of solution = $V_{1} + V_{2}$

= 21.35 mL + 25.0 mL

= 46.36 mL (1 mL = 0.001 L)

= 0.04636 L

Therefore, moles of acid required are calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.1281 M = \frac{no. of moles}{0.04635 L}\\no. of moles = 0.006 mol$

Thus, we can conclude that there are 0.006 moles of acid in the flask.

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3 years ago

A miner develops cancer of the esophagus. Ten years before, he had been exposed to radiation when he worked for a year in a mine

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D) It is unlikely that a specific cause can be determined, but the treatment would likely be the same in either case

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3 years ago

Read 2 more answers