Air at 25ºC flows in an electric hair drier with a velocity of 6 m/s perpendicular to a Nichrome heating element. The heating el
ement is 1-mm in diameter and 36-cm long with a resistance of 1.52 Ω/m. The wire temperature cannot exceed 420ºC so that the wire will not lose strength and sag. Determine the electric current in the wire.
1 answer:
Answer:
Check the explanation
Explanation:
Electrical current can be measured according to the rate of electric charge flow in any electrical circuit:
the derivative of the electric charge by time determines the momentary current.
i(t) will be the momentary current I at time t in amps (A).
Q(t) will also be the momentary electric charge in coulombs (C).
t is the time in seconds (s).
so if the current is constant:
I = ΔQ / Δt
I will be the current in amps (A).
ΔQ will be the electric charge in coulombs (C), which is expected to flows at time duration of Δt.
Δt is the time duration in seconds (s).
Kindly check the attached image below to get the step by step explanation to the question above.
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Answer:
a. which is constant therefore, n = constant
b. The temperature at the end of the process is 109.6°C
c. The work done by the balloon boundaries = 10.81 MJ
The work done on the surrounding atmospheric air = 10.6 MJ
Explanation:
p₁ = 100 kPa
T₁ = 27°C
D₁ = 10 m
v₂ = 1.2 × v₁
p ∝ α·D
α = Constant
v₂ = 1.2 × v₁ = 1.2 × 523.6 = 628.32 m³
Therefore, D₂ = 10.63 m
We check the following relation for a polytropic process;
We have;
n = -1/3
Therefore, the relation, pVⁿ = Constant
b. The temperature T₂ is found as follows;
T₂ = 300.15/0.784 = 382.75 K = 109.6°C
c.
p₂ = 100000/0.941 = 106.265 kPa
The work done by the balloon boundaries = 10.81 MJ
Work done against atmospheric pressure, Pₐ, is given by the relation;
Pₐ × (V₂ - V₁) = 1.01×10⁵×(628.32 - 523.6) = 10576695.3 J
The work done on the surrounding atmospheric air = 10.6 MJ
Answer:
(a) The velocity of the collar = 1.624er-15.54eo in/s
(b) the acceleration of the collar=-49.94er-9.74eo in/s²
(c)the acceleration of collative rod =-3.284er in/s²
Explanation:
Check attachment for calculation
