The silicon wafer contains 20.96 g of silicon.
The mole of a substance is related to its mass and molar mass by the following equation:
<h3>Mole = mass / molar mass ....... (1)</h3>
Making mass the subject of the above equation, we have
<h3>Mass = mole × molar mass ..... (2)</h3>
With the above formula (i.e equation 2), we can obtain the mass of silicon in the wafer as follow:
Mole silicon = 0.746 mole
Molar mass of silicon = 28.09 g/mol
<h3>Mass of silicon =? </h3>
Mass = mole × molar mass
Mass = 0.746 × 28.09
<h3>Mass of silicon = 20.96 g</h3>
Therefore, the mass of silicon in the wafer is 20.96 g
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Benzene is used for pesticides and detergents. It is also used for other things besides these.
CH3CH2MgBr is more soluble in diethyl ether .
We know that polar solvent dissolve in polar solvent very perfectly . as diethyl ether is a polar solvent so it have dipole -dipole interaction .
Hence the compound with similar interaction can dissolve in diethyl ether .
Here , MgBr2 is an ionic compound . there is ion-ion interactions occurs which is not similar to dipole -dipole interaction in diethyl ether .hence the solubility of MgBr2 in diethyl ether is less .
but in case of CH3CH2MgBr there are both polar and nonpolar end .CH3CH2 is the nonpolar end and MgBr is the polar end .
thus with the nonpolar end solute interact using depression forces and with polar end solute interact using dipole-dipole interaction . so CH3CH2MgBr is more soluble .
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Answer:
10.335
Explanation:
An object was carefully weighed on three different balances
Each of these balances were zeroed before weighing
The masses that were weighed are as follows
10.35 g , 10.355 g, 10.30 g
Therefore the average value of these measurements can be calculated as follows
The total number of mass is 3
= 10.30 + 10.355 + 10.30/3
= 31,005/3
= 10.335
Hence the average value of these measurements is 10.335
Answer:
Explanation:
Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical.
