Answer:
q=2313.04
T=690.86°C
Explanation:
Given that
Thickness t= 20 cm
Thermal conductivity of firebrick= 1.6 W/m.K
Thermal conductivity of structural brick= 0.7 W/m.K
Inner temperature of firebrick=980°C
Outer temperature of structural brick =30°C
We know that thermal resistance
These are connect in series
Heat transfer
So heat flux
q=2313.04
Lets temperature between interface is T
Now by equating heat in both bricks
So T=690.86°C
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer:
I = 0.625 A
Explanation:
Given that,
Power of the light bulb, P = 75 W
Voltage of the circuit, V = 120 V
We need to find the current flowing through it. We know that, Power is given by :
I is the electric current
So, the current is 0.625 A.
Explanation:
Lets take G is the incident radiation on the body.
Where
absorptive part of G
reflected part of G
transmitted part of G
lets take a is the absorptivity ,r is the reflectivity and t is the transmissivity.
So
G=a G+r G+t G
So We can say that
1=a+r+t
We can say that
absorptivity is the capacity of a body to absorb the incident radiation.
reflectivity is the capacity of a body to reflect the incident radiation.
transmissivity is the capacity of a body to transmit the incident radiation.
In the United States, fire codes are developed primarily by two model code organizations, the International Code Council (ICC) and the National Fire Protection Association (NFPA).