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-Dominant- [34]
3 years ago
5

What is happening to the protons in the nucleus and the number of orbits as you move across the periodic table from left to righ

t? What happens to the number of orbits as you move down a column on the periodic table and effective nuclear charge ?
Chemistry
1 answer:
baherus [9]3 years ago
6 0

Explanation:

As you move across the periodic table, the number of protons and neutrons increases but the number of orbital levels of the period remains the same. The atomic radii therefore decrease, across the period, because the increase in proton number causes an increased pull of the orbital electrons bringing them closer to the nucleus.

As you move down a group in a periodic table, the number of orbital levels increase.  The effective nuclear charge of the nucleus of the atoms decreases due to the increased number of orbital levels that shield the valence electrons from the attractive force nucleus.

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Elements
Snezhnost [94]

Answer:

elements are composed of

electrons with a little mass and negative charge

protons with mass and positive charge

neutrons with mass and no charge

isotopes same number of protons, different in neutrons

share me the other part of the photo to complete!!!

7 0
3 years ago
What is the pH of a solution that has a hydronium ion concentration 100 times less than a solution with a pH of 6 explain your r
aksik [14]

Answer:

4

Explanation:

cuz i just took a test and the question was this just reversed. if the ph is 4 and the other ph is 100x greater it’s 6. i don’t kno the reasoning lol

4 0
3 years ago
6th grade help me pleaseeeee
Vesnalui [34]

Answer:

the answer would be A. cells

Explanation:

just trust me Im a 8th grader and I did that before

7 0
3 years ago
One quarter of a 1-mole piece of iron turns to rust in six months. Which rate describes the speed at which the iron rusts?
avanturin [10]
1/4 mol = 0.25 mol

6 months = 0.5 year

rate = 0,25 mol / 0.5 year = 0.5 mol/year or approx 0.042 mol/month
7 0
3 years ago
Read 2 more answers
A. 1720 kJ<br> B. 125.6 kJ<br> C. 3440 kJ<br> D. 4730 kJ
Feliz [49]

Answer:

Q = 3440Kj

Explanation:

Given data:

Mass of gold = 2kg

Latent heat of vaporization = 1720 Kj/Kg

Energy required to vaporize 2kg gold = ?

Solution:

Equation

Q= mLvap

It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg

by putting values,

Q= 2kg ×  1720 Kj/Kg

Q = 3440Kj

7 0
3 years ago
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