In Atomic Absorption Spectrophotometry, narrow atomic lines are desirable. However, line broadening arises from: (a) Jablonski e
1 answer:
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Answer: a)
b) : acid
:conjugate base.
And, : base
: conjugate acid.
c)
d)
e)
Explanation:
a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases ions in their aqueous states.
The equation for the dissociation of acid is given by:
b) According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given chemical equation:
is loosing a proton, thus it is considered as an acid and after losing a proton, it forms
which is a conjugate base.
And, is gaining a proton, thus it is considered as a base and after gaining a proton, it forms
which is a conjugate acid.
c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.
d) The chemical equation for dissociation of in water.
e) The chemical equation for the reaction of and
Answer:
69.8 kilo Pasacl is the pressure of the hydrogen gas.
Explanation:
Pressure at which hydrogen gas collected = p = 101.2 kilo Pascals
Vapor pressure water = = 31.4 kilo Pascals
The pressure of hydrogen gas = P
The pressure at which gas was collected was sum of vapor pressure of water and hydrogen gas.
69.8 kilo Pasacl is the pressure of the hydrogen gas.
To create the Lewis structure we need to take into account the octet rule: atoms tend to gain, lose or share electrons to complete their valence shell with 8 electrons.
C belongs to Group 4A in the periodic table so it has 4 valence electrons. It needs to share 4 pairs of electrons to complete the octet.
F belongs to Group 7A in the periodic table so it has 7 valence electrons. Each F needs to share 1 pair of electrons to complete the octet.
As a consequence, in CF₄, C will form a single bond with each F and all the octets will be complete.
