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Alexus [3.1K]
3 years ago
12

Can someone please help me ​

Physics
1 answer:
Tamiku [17]3 years ago
4 0

<em>F</em> = 153 N

\theta = 11.3°

Explanation:

Let us define first our directional convention. Anything pointing up or to the right is considered positive and anything pointing down or to the left is considered negative. Now let's look at the components F_{x} and F_{y}:

F_{x} = 350 N - 200 N = 150 N

F_{y} = 180 N - 150 N = 30 N

The magnitude of the resultant force <em>F</em> is given by

F = \sqrt{F_{x}^{2}+F_{y}^{2}}

\:\:\:\:\:\:= \sqrt{(150\:N)^{2}+(30\:N)^{2}}

\:\:\:\:\:\:=153\:N

To find the direction \theta, we use

\tan \theta = \dfrac{F_{y}}{F_{x}}=\dfrac{30\:N}{150\:N}=0.2

or

\theta = \tan^{-1}(0.2) = 11.3°

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