Answer:
That is, the molar mass of a substance is the mass (in grams per mole) of 6.022 × 10 23 atoms, molecules, or formula units of that substance. In each case, the number of grams in 1 mol is the same as the number of atomic mass units that describe the atomic mass, the molecular mass, or the formula mass, respectively.
The time taken for the same volume of methane gas to diffuse is 7.1 s.
<h3>
Rate of gas diffusion</h3>
The rate at which a given mass of diffuses is inversely proportional to the molar mass of the gas.
![\frac{t_2}{t_1} = \sqrt{\frac{M_2}{M_1} }](https://tex.z-dn.net/?f=%5Cfrac%7Bt_2%7D%7Bt_1%7D%20%3D%20%5Csqrt%7B%5Cfrac%7BM_2%7D%7BM_1%7D%20%7D)
where;
- M1 is the molar mass of methane (CH4) = 16 g
- M2 is the molar mass of hydrogen as = 2
- t1 is time taken for methane = 20 s
- t2 is the time taken for hydrogen = ?
![\frac{t_2}{t_1} = \sqrt{\frac{M_2}{M_1} }\\\\\frac{t_2}{20} = \sqrt{\frac{2}{16} }\\\\\frac{t_2}{20} = \frac{\sqrt{2} }{4} \\\\t_2 = \frac{20\sqrt{2} }{4} \\\\t_2 = 5\sqrt{2} \\\\t_2 = 7.1 \ s](https://tex.z-dn.net/?f=%5Cfrac%7Bt_2%7D%7Bt_1%7D%20%3D%20%5Csqrt%7B%5Cfrac%7BM_2%7D%7BM_1%7D%20%7D%5C%5C%5C%5C%5Cfrac%7Bt_2%7D%7B20%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B2%7D%7B16%7D%20%7D%5C%5C%5C%5C%5Cfrac%7Bt_2%7D%7B20%7D%20%3D%20%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B4%7D%20%5C%5C%5C%5Ct_2%20%3D%20%5Cfrac%7B20%5Csqrt%7B2%7D%20%7D%7B4%7D%20%5C%5C%5C%5Ct_2%20%3D%205%5Csqrt%7B2%7D%20%5C%5C%5C%5Ct_2%20%3D%207.1%20%5C%20s)
Thus, the time taken for the same volume of methane gas to diffuse is 7.1 s.
Learn more about rate of gas diffusion here: brainly.com/question/26696466
Answer:
b. gelatin
Explanation:
a homogeneous noncrystalline consisting of large molecules or ultramicroscopic particles of one substance.
Answer:
Ba^2+ (aq) +SO4^2- (aq) →BaSO4(s)
Explanation:
you really need to learn how to do this yourself - its really important throughout level chem, pre-ap chem, and especially if you plan on moving on to ap chem!!