Answer:
Primary succession is one of two types of biological and ecological succession of plant life, occurring in an environment in which new substrate devoid of vegetation and other organisms usually lacking soil, such as a lava flow or area left from retreated glacier, is deposited.
Given:
u = 10⁵ m/s, the entrance velocity
v = 2.5 x 10⁶ m/s, the exit velocity
s = 1.6 cm = 0.016 m, distance traveled
Let a = the acceleration.
Then
u² + 2as = v²
(10⁵ m/s)² + 2*(a m/s²)*(0.016 m) = (2.5 x 10⁶ m/s)²
0.032a = 6.25 x 10¹² - 10¹⁰ = 6.24 x 10¹²
a = 1.95 x 10¹⁴ m/s²
Answer: 1.95 x 10¹⁴ m/s²
Answer:
"Planets May Affect the Chemistry of Their Stars. Planets are, by and large, at the mercy of their stars. Not only do stars provide a ready energy source of radiated light and heat, but the mass and gravitational pull of stars flat-out dwarfs the summed masses and pulls of any orbiting companions."
Answer:
The answer is below
Explanation:
Firstly, the frequency is received by the wall and then it is reflected and received by the bat.
The frequency received by the wall (f') is given by:
f' = 
The - sign is used when the observer is moving away from the source and + sign when the observer is moving towards the source.
Since the bat is moving towards the wall, we use a positive sign. Hence:
f' = 
The frequency reflected and received by the bat f" is:
f'' = 
- sign is used when the source moves toward the observer and + is used when the source moves away
since the bat moves towards the wall, then::
f'' = 
v = speed of sound in air = 331 m/s, vo = velocity of observer = 5 m/s, vs = velocity of source = 5 m/s. Therefore:

Answer: 9 days
Explanation:
Let the rate of Leaf growth <em>r</em> be defined as,
= 
where <em>A</em> is initial area of the leaf, <em>A1</em> is the final area of the leaf and<em> t</em> is the time taken for the increase in Area.
- Express the proportional relationship in equation.
Given that rate of leaf growth, r is proportional to the surface area of the leaf A. we have r ∝ A.
r = kA, where k is the rate constant.
therefore, k = 
when A = 2
, A1 = 3
so k = 
=
÷ 2
= 0.33 ÷ 2
k = 0.167
- After calculating the rate constant k, we then find the time t when A1 is 5

- we have r = k × A1 =

so, 0.167 × 2 = 
0.33 =
.
t = 3/0.33
Therefore, t = 9 days.