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allsm [11]
3 years ago
15

A large, massive object collides with a stationary, smaller object on an ice rink. If the large object transfers all of its mome

ntum to the smaller object, which statement below describes the velocity of the smaller object after the collision?
A. It will move faster than the large object was moving initially.


B. It won't move.


C. It will move at the same speed that the large object was moving initially.


D. It will move slower than the large object was moving initially.
Physics
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

a ut will move faster than the large object was moving initially

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Primary succession is one of two types of biological and ecological succession of plant life, occurring in an environment in which new substrate devoid of vegetation and other organisms usually lacking soil, such as a lava flow or area left from retreated glacier, is deposited.

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The electrons that produce the picture in a
vredina [299]
Given:
u = 10⁵ m/s, the entrance velocity
v = 2.5 x 10⁶ m/s, the exit velocity
s = 1.6 cm = 0.016 m, distance traveled

Let a = the acceleration.
Then
u² + 2as = v²
(10⁵ m/s)² + 2*(a m/s²)*(0.016 m) = (2.5 x 10⁶ m/s)²
0.032a = 6.25 x 10¹² - 10¹⁰ = 6.24 x 10¹²
a = 1.95 x 10¹⁴ m/s²

Answer: 1.95 x 10¹⁴ m/s²

4 0
3 years ago
PLEASE HELP ASAP!!! THANKS!<br><br> how do stars and planets effect eachother?
Serhud [2]

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6 0
3 years ago
Read 2 more answers
A bat, flying at 5.00 m/s, emits a chirp at 40.0 kHz. If this sound pulse is reflected by a wall, what is the frequency of the e
fredd [130]

Answer:

The answer is below

Explanation:

Firstly, the frequency is received by the wall and then it is reflected and received by the bat.

The frequency received by the wall (f') is given by:

f' = f(v\pm v_o)/v\\\\

The - sign is used when the  observer is moving away from the source and + sign when the observer is moving towards the source.

Since the bat is moving towards the wall, we use a positive sign. Hence:

f' = f(v+ v_o)/v\\\\

The frequency reflected and received by the bat f" is:

f'' = f'\frac{v}{ (v\pm v_s)}\\\\

- sign is used when the source moves toward the observer and + is used when the source moves away

since the bat moves towards the wall, then::

f'' = f'\frac{v}{(v-v_s)} =\frac{f(v+v_o)}{v}*\frac{v}{(v-v_s)} =f\frac{(v+v_o)}{(v-v_s)}  \\\\

v = speed of sound in air = 331 m/s, vo = velocity of observer = 5 m/s, vs = velocity of source = 5 m/s. Therefore:

f"=f\frac{(v+v_o)}{(v-v_s)} =40\ kHz\frac{(331\ m/s+5\ m/s)}{(331\ m/s+5\ m/s)} \\\\f"=41\ kHz

3 0
3 years ago
How quickly a leaf grows is proportional how big [ie the surface area] the leaf is. If the area of the leaf grows from 2cm2 to 3
marusya05 [52]

Answer: 9 days

Explanation:

  • Step 1

Let the rate of Leaf growth <em>r</em> be defined as, \frac{Increase  in  area}{time taken} = \frac{A1 - A}{t}

where <em>A</em> is initial area of the leaf, <em>A1</em> is the final area of the leaf and<em> t</em> is the time taken for the increase in Area.

  • Express the proportional relationship in equation.

Given that rate of leaf growth, r is proportional to the surface area of the leaf A. we have r ∝ A.

r = kA, where k is the rate constant.

therefore, k = \frac{r}{A}

when A = 2cm^{2}, A1 = 3

so k = \frac{\frac{3 - 2}{3}}{2}

= \frac{1}{3} ÷ 2

= 0.33 ÷ 2

k = 0.167

  • After calculating the rate constant k, we then find the time t when A1 is 5cm^{2}
  • we have r = k × A1 = \frac{A1 - A}{t}

so, 0.167 × 2 = \frac{5 - 2}{t}

0.33 = \frac{3}{t}.

t = 3/0.33

Therefore, t = 9 days.

3 0
4 years ago
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