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kondor19780726 [428]
4 years ago
5

The wavelength of visible light is about 5500 times longer than the wavelength of x-rays. If you represent the wavelenth of an x

-ray photon by a line 1 inch long, how long a line (in feet) must you draw to represent the wavelength of visible light?
Physics
1 answer:
Pie4 years ago
6 0

Answer:

458.33 ft

Explanation:

We are given that

Wavelength of of an x- ray photon=1 in

Wavelength of of an x- ray photon==\frac{1}{12}ft

1 in=\frac{1}{12}feet

We have to find the  length of line (in feet) drawn by you to represent the wavelength of visible light.

According to question

Wavelength of visible light=5500\times \frac{1}{12} ft

Wavelength of visible light=\frac{5500}{12}ft

Wavelength of visible light=458.33 ft

Hence, the 458.33 ft line must drawn  by you to represent the wavelength of visible light.

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A merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m
arlik [135]

Answer:

A.) 4 revolution

B.) 0.2 revolution

C.) 4 seconds

D.) 2.75 m/s

Explanation:

Given that a merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m

Solution

1 revolution = 2πr

Where r = 1.75m

A. How many revolutions will it make in 3 minutes?

(2π × 1.75) / 3

10.9955 / 3

3.665 RPM

Number of revolution = 15 / 3.665

Number of revolution = 4 revolution

B. How many revolutions will it make in 10.0 seconds?

First convert 10 seconds to minutes

10/60 = 0.167 minute

(2π × 1.75) / 0.167

10.9955 / 0.167

65.973

Number of revolution = 15 / 65.973

Number of revolution = 0.2 revolution

C. How long does it take for a person to make 1 complete revolution?

15 = 1 / t

Make t the subject of formula

t = 1/15

t = 0.0667 minute

t = 4 seconds

D. What is the velocity in m/s of person standing on its edge?

Velocity in m/ s will be:

Velocity = (15 × 2pi × r) / 60

Velocity = 164.9334 / 60

Velocity = 2.75 m/s

8 0
3 years ago
How much time is needed for a car to accelerate from 2.0 m/s to a speed of 6.0 m/s if its acceleration is 10 m/s^2
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A baseball was hit and reached its maximum height in 3.00s. Find (a) its initial velocity; (b) the height it reaches.[29.4 m/s;
kicyunya [14]

Answer:

u= 29.43 m/s

h=44.14 m

Explanation:

Given that

t= 3 s

We know that acceleration due to gravity ,g = 9.81 m/s² (Downward)

Initial velocity  = u

Final velocity ,v= 0 (At maximum height)

We know v = u +a t

v=final velocity

u=initial velocity

a=Acceleration

Now by putting the values in the above equation

0 = u - 9.81 x 3

u= 29.43 m/s

The maximum height h is given as

v² = u ² -  2 g h

0² = 29.43 ² - 2 x 9.81 x h

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4 years ago
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