Answer: B. Turning on your hazard lights.
Explanation:
Because...
that indicates the drive behind you to go in front of you and indicator lights that flash in unison to warn other drivers that the vehicle is a temporary obstruction.
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Answer:
The Reynold Number is 146415.34
Explanation:
The density of ethyl alcohol = ρ = 789 kg/m^3
The dynamic viscosity of ethyl alcohol = μ = 0.001095 kg/m.s
Velocity = V = 4 m/s
Diameter of pipe = D = 2 in = 0.0508 m
The Reynold's number (Re), will be:
Re = ρVD/μ
Re = (789 kg/m^3)(4 m/s)(0.0508 m)/(0.001095 kg/ms)
<u>Re = 146415.34</u>
Answer:
c) site preparation
Explanation:
A construction process can be defined as a series of important physical events (processes) that must be accomplished during the execution of a construction project.
Generally, in the construction of any physical asset such as offices, hospitals, schools, stadiums etc, the first step of the construction process is site preparation. Site preparation refers to processes such as clearing, blasting, levelling, landfilling, surveying, cutting, excavating and demolition of all unwanted objects on a piece of land, so as to make it ready for use.
This ultimately implies that, site preparation should be the first task to be accomplished in the construction process.
Hence, the construction process typically begins with site preparation before other activities such as the laying of foundation can be done.
Additionally, construction costs can be defined as the overall costs associated with the development of a built asset, project or property. The construction costs is classified into two (2) main categories and these are; capital and operational costs.
Explanation:
voltage, current and resistance are the Volt [ V ], Ampere [ A ] and Ohm [ Ω ]
Answer:
T = 15 kN
F = 23.33 kN
Explanation:
Given the data in the question,
We apply the impulse momentum principle on the total system,
mv₁ + ∑ = mv₂
we substitute
[50 + 3(30)]×10³ × 0 + FΔt = [50 + 3(30)]×10³ × ( 45 × 1000 / 3600 )
F( 75 - 0 ) = 1.75 × 10⁶
The resultant frictional tractive force F is will then be;
F = 1.75 × 10⁶ / 75
F = 23333.33 N
F = 23.33 kN
Applying the impulse momentum principle on the three cars;
mv₁ + ∑ = mv₂
[3(30)]×10³ × 0 + FΔt = [3(30)]×10³ × ( 45 × 1000 / 3600 )
F(75-0) = 1.125 × 10⁶
The force T developed is then;
T = 1.125 × 10⁶ / 75
T = 15000 N
T = 15 kN