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3 years ago

At what wind speed does a snowstorm become a blizzard?

1 answer:

5 0

To be a blizzard, a snow storm must have sustained winds or frequent gusts that are greater than or equal to 56 km/h (35 mph) with blowing or drifting snow which reduces visibility to 400 m or 0.25 mi or less and must last for a prolonged period of time—typically three hours or more.

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An electrician finds that a 0.6 m length of a certain type of wire has a resistance of 0.13 Ω . What is the total resistance of

Tamiku [17]

Answer:

Explanation:

For resistance the formula is as follows

R = ρ L/S

where L is length of the wire , ρ is a constant for a specific material called specific resistance and S is cross sectional area .

For 0.6 m wire , putting the values

.13 = ρ x 0.6 / S

For unknown wire

R = ρ x 187 / S

Dividing the two equations

R / .13 = 187 / .6

R = (.13 x 187) / .6

= 40.5 ohms .

8 0

3 years ago

Pluto has a shape that is nearly round,and it orbits the sun,it has five known moons.why is it called a dwarf planet and not a p

s2008m [1.1K]

There are three things needed to be classified as a planet.

Pluto meets 2 of the 3.

The one it does not meet is it doesn’t “clear the neighborhood” which means a planet needs to be gravitationally dominant over all objects around it. Meaning smaller bodies ( asteroids) would either combine with the larger body making it bigger or pushing them away ( out of their orbit) so they do not collide with the larger body.

8 0

3 years ago

A message is sent from the Galileo spacecraft orbiting Jupiter to earth at a distance of 928,000,000km. If it took the signal 51

expeople1 [14]

The answer would approximately be 299,741.60

6 0

3 years ago

Read 2 more answers

If a planet has 3 times the radius of the Earth, but has the same density as the Earth, what is the gravitational acceleration a

xz_007 [3.2K]

Answer:

The Gravitational Acceleration of the Big planet is G = 3g

where G is the gravitational acceleration of the Big Planet and g is the gravitational acceleration of the Earth

So, it becomes G = 3 x 9.8 $ms^{-2}$

G = 29.4 $ms^{-2}$

Explanation:

Let's start by calculating the Density of the Earth of mass m anad Radius r

We know that mass is density times the volume

ρ = $\frac{m}{V}$

m = ρV

we know the volume is V = $\frac{4}{3}$ $πr^{3}$ (please ignore the symbol of Pi)

m = ρ $\frac{4}{3}$ $πr^{3}$

Calculating the Density of Big Planet

→For Big Planet we know that radius is 3-times the radius of Earth, that is 3r

M = ρ $\frac{108}{3}$ $π(r)^{3}$

So in conclusion, the mass of Earth and the mass of Big planet are related as M = 27m

Now let's come to the Gravitational Force, we know that gravitational force is directly proportional to the mass of the body and inversely proportional to the radius.

→Suppose for Earth: Mass = m, Radius = r

For Big Planet: Mass = M, Radius = R

$\frac{m}{r^{2} }$ : $\frac{M}{R^{2} }$ = g : G

$\frac{Gm}{r^{2} }$ = $\frac{gM}{R^{2} }$

G = $\frac{gMr^{2}}{mR^{2}}$

→ Putting the value of R = 3r and M = 27m

G = $\frac{g27mr^{2}}{m(3r)^{2}}$

By cutting the terms, we get

G = 3g

value of g= 9.8 $ms^{-2}$

G = 3 x $9.8ms^{-2}$

G = 29.4 $ms^{-2}$

5 0

4 years ago

A marble on a frictionless track, starting from point A in the drawing, is projected down the curved runway. (This means that th

EleoNora [17]

Answer:

v = 4.4 m / s

Explanation:

Unfortunately, the exercise scheme does not appear. Let's analyze the problem the marble leaves point A with an initial velocity, goes down and then rises to a given height where its velocity is zero, in the whole trajectory they tell us that the resistance is zero, so we can use the conservation relations of the enegy.

Starting point. Point A

Em₀ = K + U = ½ m v2 + mg y_a

point B.

Em_f = U = m g y

the energy is conserved

Em₀ = Em_f

½ m v² + mg y_a = m g y

½ m v² = m g (y -y_a)

v = $\sqrt {2g ( y - y_a)}$

In the exercise the diagram is not seen, but the height of point A must be known, suppose that y_a = 4 m

v = $\sqrt{ 2 \ 9.8 ( 5 -4)}$

v = 4.4 m / s

4 0

3 years ago