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Digiron [165]
3 years ago
5

Estimate the frequency of vibration of your arm.

Physics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

0.7945 Hz

Explanation:

Data provided in the question:

Length of the arm = 0.59 m

Since the center of mass lies at about \frac{2}{3} of its length

Thus,

Length of the simple pendulum = \frac{2}{3} × 0.59 m = 0.3933 m

Now,

Frequency of vibration, f = \frac{1}{2\pi}\sqrt\frac{g}{l}

Thus,

we have,

Frequency of vibration for the arm = \frac{1}{2\pi}\sqrt\frac{9.8}{0.3933}

or

Frequency of vibration for the arm = 0.7945 Hz

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An electric motor has a rating of 4.0 x 10^2 watts. How much time will it take for this motor to lift a 50.-kilogram mass a vert
LenKa [72]
ΔT = ?

P = 50 kg

ΔS = 8.0 m

g = 9.8 m/s²

Pot = 4,0x10² W

Find the time :

ΔT = P * g *  ΔS / Pot

ΔT = 50 * 9.8 * 8.0 / 4.0x10²

ΔT = 3920 / 4x10²

ΔT = 9.8 S

hope this helps!


4 0
3 years ago
Explain ways that weak and strong nuclear forces are alike.
larisa [96]
They both use messenger particles to carry the force. Gluons for the strong force and W and Z for the weak. And both sets of particles solely with the sub atomic particles of the nuclei: quarks and neutrinos. That is, their range is limited to the nuclei of the atoms and the ions.
8 0
3 years ago
Tyler is in downtown San Antonio entertaining the tourists with amazing feats of physics. He carries a nickel
professor190 [17]

Answer:

The velocity of the nickel just before it hits the ground is approximately 49.3 m/s

Explanation:

In order to calculate the velocity of the nickel just before it hits the ground, we recall the kinematic equation of motion, v² = u² + 2·g·h, where the variables of the equation are defined as follows;

v = The velocity of the nickel just before it hits the ground after it is pushed off the observation deck

u = The initial velocity of the nickel just before it is pushed off the observation deck = 0 m/s

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which he nickel is pushed off the edge = 124 m

Substituting the given values and the constant, "g", we have;

v² = 0² + 2 × 9.8 × 124 = 2,430.4

v = √2,430.4

Using a graphing calculator, we have;

v = √2,430.4 = 14·√(62/5) ≈ 49.3

The velocity of the nickel just before it hits the ground = v ≈ 49.3 m/s.

3 0
3 years ago
What Grade will you give my One Pager so Far?
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Answer:

98

Explanation:

7 0
3 years ago
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Suppose that a sound source is emitting waves uniformly in all directions. If you move to a point twice as far away from the sou
Helen [10]

Answer:

<em>d. unchanged.</em>

Explanation:

The frequency of a wave is dependent on the speed of the wave and the wavelength of the wave. The frequency is characteristic for a wave, and does not change with distance. This is unlike the amplitude which determines the intensity, which decreases with distance.

In a wave, the velocity of propagation of a wave is the product of its wavelength and its frequency. The speed of sound does not change with distance, except when entering from one medium to another, and we can see from

v = fλ

that the frequency is tied to the wave, and does not change throughout the waveform.

where v is the speed of the sound wave

f is the frequency

λ is the wavelength of the sound wave.

4 0
3 years ago
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