Metering valves. These valves should be initially adjusted to provide adequate lubrication to each location
Answer:
Rate of heat loss per unit length of pipe, q' = 767.01 W/m
Explanation:
Let q' be the Rate of heat loss per unit length
Let q be the Rate of heat loss
q' = q/L
Where L is the length of the pipe
Diameter, D= 0.6m
The rate of heat loss q is given by the formula: q = Sk(T₂ - T₁)
Where k is the thermal conductivity of the concrete at 300 K
k = 1.4 Wb/m-K (at 300K)
And S is the shape factor given by the formula:
S = 2πL/ ln(1.08w/D)
S = (2π*L) / ln(1.08*1.75/0.6))
S = (2π*L) / 1.147
S = 5.48 L
q = 5.48L*1.4(400-300)
q = 767.01 L
q' = q/L
q' = 767.01L/L
q' = 767.01 W/m
Answer:
The statement regarding the mass rate of flow is mathematically represented as follows
Explanation:
A junction of 3 pipes with indicated mass rates of flow is indicated in the attached figure
As a basic sense of intuition we know that the mass of the water that is in the pipe junction at any instant of time is conserved as the junction does not accumulate any mass.
The above statement can be mathematically written as
this is known as equation of conservation of mass / Equation of continuity.
Now we know that in a time 't' the volume that enter's the Junction 'O' is
1) From pipe 1 =
1) From pipe 2 =
Mass leaving the junction 'O' in the same time equals
From pipe 3 =
From the basic relation of density, volume and mass we have
Using the above relations in our basic equation of continuity we obtain
Thus the mass flow rate equation becomes