Question

Find the gravitational potential at a point on the earth surface. Take mass as of earth as 5.98×10^24kg,it's radius as6.38×10^6nand G=6.67×10^-11Nm^2kg^-2​

Answer 1

Answer:

$-6.25\cdot 10^7 J$

Explanation:

The gravitational potential at a point on the Earth surface is given by:

$U=-\frac{GM}{R^2}$

where

G=6.67×10^-11Nm^2kg^-2 is the gravitational constant

M=5.98×10^24kg is the Earth's mass

R=6.38×10^6 m is the Earth's radius

Substituting the numbers into the equation, we find

$U=-\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.38\cdot 10^6)}=-6.25\cdot 10^7 J$