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just olya [345]
4 years ago
11

How inertia changes the effects of gravity on objects in the solar system

Physics
2 answers:
ArbitrLikvidat [17]4 years ago
7 0

Answer: d,prevents planets from pulling into one another. on edge nuity

Explanation:

just took the test and got it right!

aalyn [17]4 years ago
5 0

Answer:

Explanation:

tendency to resist change is called inertia, and its interaction with the gravitational attraction of the sun is what keeps the planets of the solar system, including Earth, in stable orbits.

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Identify the amplitude in the wave image below.*<br> F. G H J
alina1380 [7]
Answer:F
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3 years ago
What does the 2 mean in the formula 5Mg3(PO4)2?
stira [4]
D. There are two phosphate ions in a molecule of magnesium phosphate
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3 years ago
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The weight of a person is 500N and his foot imprint area is 0.5m^2.Calculate the total pressure exerted by person when he stands
Ghella [55]

Answer:

Pressure on both feet will be 500N/m^2  

Explanation:

Weight of the person F = 500 N

Area of foot print A=0.5m^2

Area of both the foot A=2\times 0.5=1m^2

We have to find pressure on both the feet

Pressure is equal to ratio of force and area

So pressure P=\frac{F}{A}

P=\frac{500}{1}=500N/m^2

So the pressure on both feet will be 500N/m^2 when person stands on both feet.

7 0
4 years ago
a glass bottle of soda is sealed with a screw cap the absolute pressure of the gas inside the bottle is 1.80*10^5 pa. assuming t
eduard

The force exerted by a pressure of any gas over a surface its given by the formula P=F/S (where P is pressure, F force and S surface).

We can multiply both sides of the formula by S to obtain the force.

P*S=(F*S)/S

P*S=F

Solve for P=1.80*10^5 Pa and S=4.10*10^-4 m^2 ([Pa] =[N/m^s])

(1.80*10^5 N/m^s) * (4.10*10^-4 m^2) =F

73.8 N =F

8 0
3 years ago
A 1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0.20 km. What is the magnitude of the fri
omeli [17]

Answer:

4500 N

Explanation:

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a = v^2/r

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Therefore, a body with mass m, will feel a force f:

f = m v^2/r

Therefore we need another force to keep the body(car) from sliding, this will be given by friction, remember that friction force is given a the normal times a constant of friction mu, that is:

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The car will not slide if     f = fs,   i.e.

fs = μmg =  m v^2/r

That is, the magnitude of the friction force must be (at least) equal to the force due to the centripetal acceleration

fs = (1000 kg)  * (30m/s)^2 / (200 m) = 4500 N

7 0
4 years ago
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