1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kaylis [27]
3 years ago
7

The MSDS for chloroform indicates that it is a clear liquid that has a pleasant smell and substantial vapor pressure. People sho

uld avoid inhaling its vapors, and it is sensitive to light. Malik needs 10 mls of chloroform for an experiment.
According to this information, how should he safely pour the chloroform?

He should locate the chloroform stored in a transparent container in chemical storage and pour directly into his beaker from that location.

He should locate the chloroform stored in a transparent container in chemical storage and should take it to the fume hood to pour.

He should locate the chloroform stored in a dark container in chemical storage and should take it to the fume hood to pour.

He should locate the chloroform stored in a dark container in chemical storage and pour directly into his beaker from that location.
Physics
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer:

The correct option is the third option

Explanation:

Firstly, it must be noted that chemicals/reagents that are sensitive to sunlight are stored in dark/amber container in the laboratory. Hence, the chloroform can only be found in an amber/dark bottle.

Also, reagents/chemicals that release poisonous/offensive gases are handled in the fume cupboard in the laboratory. Thus, If Malik is going to pour the chloroform, he should pour it in a fume cupboard to avoid inhaling it because of the toxicity of it's vapor.

From the above explanation, it can be deduced that <u>Malik should locate the chloroform stored in a dark container in chemical storage and should take it to the fume hood to pour</u>.

You might be interested in
What is an<br> example of a force?<br> Pressure<br> Power<br> Energy<br> Weight
Kryger [21]

Answer:

weight

Explanation:

weight is the pull of gravity so its a force !!

5 0
3 years ago
Accuracy in scientific investigation is important because
77julia77 [94]
It ensures good results
6 0
4 years ago
What would result from under-coverage?
Sunny_sXe [5.5K]
C. a lack of accurate results


hope this helps
6 0
3 years ago
Define average velocity and instantaneous velocity when are they same ​
Vlada [557]

Answer:

Look to the explanation

Explanation:

<u><em>Average velocity:</em></u> is the average rate of change of displacement with

respect to time

Average velocity is a measure for distance traveled in a given time

We can calculate the average velocity by the rule v=\frac{s}{t}

where s is the displacement and t is the time

<u><em>Instantaneous velocity:</em></u> is the velocity of an object in motion at a

specific point (x , t)

instantaneous velocity is the limit of velocity as the change in time

approaches zero

We can calculate the instantaneous velocity by the rule v=\frac{ds}{dt}

<u>Average velocity</u> is <u>equal</u> to the <u>instantaneous velocity</u> when

<u>acceleration</u> is <u>zero</u>

5 0
3 years ago
A balloon rises at the rate of 8 feet per second from a point on the ground 12 feet from an observer. To 2 decimal places in rad
Hitman42 [59]

Answer:

\displaystyle \theta' =0.24\ rad/s

Explanation:

<u>Rate Of Change</u>

Let some variable y depend on time t. we can express y as a function of t as

y=f(t)

The instant rate of change of y respect to t is the first derivative, i.e.

y'=f'(t)

The balloon, the ground and the observer form a right triangle (shown below) where the height of the balloon y, the horizontal distance x, and the angle of elevation are related with the trigonometric formula

\displaystyle tan\theta =\frac{y}{x}

Since x is constant, we take the derivative with respect to time  by using the chain rule:

\displaystyle sec^2\theta \ \theta' =\frac{y'}{x}

Solving for \theta'

\displaystyle \theta' =\frac{y'}{xsec^2\theta}

Let's compute the actual angle with the initial conditions y=9 feet, x=12 feet

\displaystyle tan\theta =\frac{y}{x}

\displaystyle tan\theta =\frac{9}{12}=\frac{3}{4}

Knowing that

\sec^2\theta=1+tan^2\theta

\displaystyle \sec^2\theta=1+\left(\frac{3}{4}\right)^2

\displaystyle \sec^2\theta=\frac{25}{16}

The balloon is rising at y'=8 feet/sec, thus we compute the change of the angle of elevation:

\displaystyle \theta' =\frac{8}{12\ \frac{25}{16}}

\displaystyle \theta' =\frac{32}{75}\ rad/s

\boxed{\displaystyle \theta' =0.43\ rad/s}

6 0
4 years ago
Other questions:
  • Lewis base A. Provides H in water Bronsted-Lowry acid B. Provides OH - in water Arrhenius base C. Proton donor D. Proton accepto
    10·1 answer
  • Add the vectors:
    10·1 answer
  • If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculat
    9·2 answers
  • The Brazilian rain forest is an area with significant biodiversity. As the rain forest is replaced with agricultural land, it is
    9·2 answers
  • Please help me this is timed . <br> Find x if a = 3.0 m/s^2
    6·1 answer
  • In a position vs. time graph, which of the following relationships is true? O The steeper the line the slower the velocity O The
    11·1 answer
  • A car starts from rest and gains a velocity of 20 m/s in 10 s.Calculate acceleration​
    8·2 answers
  • How many meters across is a road sign that has an angular size of 120 arcseconds and is 1 km away?
    5·1 answer
  • You fire a paintball from a paintball gun straight up into the air at 25.0 m/s. What is the ball velocity at the higher point th
    5·1 answer
  • hi friends how are you I am fine but I am positive coronavirus I am very poor my father my mother my brother my sister was coron
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!