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3 years ago

List 3 things that happen at the endpoint or equivalence point.

1 answer:

7 0

The equivalence point is the point in a titration where the amount of titrant added is enough to completely neutralize the analyte solution. The moles of titrant (standard solution) equal the moles of the solution with unknown concentration. ... The equivalence point is not the same as the endpoint of a titration.

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32.Alpha particles and beta particles differ in

Aleks04 [339]

The answer is C. Alpha particles are simply helium-4 nuclei, with 2 protons and 2 neutrons. Charge is 2+, and mass is on the order of 4amu. Beta particles are either electrons or positrons, with charges of 1- and 1+ respectively. Their masses are fractions of amu, so alpha particles and beta particles differ in both mass and charge.

4 0

4 years ago

Read 2 more answers

What does the specific heat for a substance indicate? A. the heat released when 1 gram of the substance burns B. the amount of h

Viktor [21]

B. the amount of heat required to increase the temperature of 1 gram by 1oC

4 0

3 years ago

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At 500°C the equilibrium constant, Kp, is 4.00 × 10–4 for the equilibrium: 2HCN(g) H2(g) + C2N2(g) What is Kp for the following

Andrews [41]

<u>Answer:</u> The value of $K_p$ for the equation is $2.5\times 10^3$

<u>Explanation:</u>

The given chemical reaction is:

$2HCN(g)\rightleftharpoons H_2(g)+C_2N_2(g);K_1$

The chemical equation for which the equilibrium constant is to be calculated follows:

$H_2(g)+C_2N_2(g)\rightleftharpoons 2HCN(g);K_p$

As, the equation is the result of the reverse of given reaction. So, the equilibrium constant for the equation will be the inverse of equilibrium constant for the given reaction.

The value of equilibrium constant for the equation is:

$K_p=\frac{1}{K_1}$

We are given:

$K_1=4.00\times 10^{-4}$

Putting values in above equation, we get:

$K_p=\frac{1}{4.00\times 10^{-4}}=2.5\times 10^3$

Hence, the value of $K_p$ for the equation is $2.5\times 10^3$

3 0

4 years ago

4P+ 5O2 -> P4O10

Ratling [72]

If 4 moles of P is used by 5 mole of O2
then....0.489 moles will be used by 5/4 × .489 = .611 moles of O2

so .611 moles

so if 4 moles of P is burnt , 1 mole of P4O10 is produced ....so for .489 moles...... .489/4=.122 moles !
so mass will be .122× 283.89 = 34.7 grams

so first ans is .611 moles and second is 34.7 grams !

if you have any problem regarding this , just comment !!!

4 0

3 years ago

Read 2 more answers

PLEASE HELP i’ll mark brainliest ( reporting fake answers)

kherson [118]

Delta S reaction= Delta S products- Delta S reactants

don't forget to mulitiply by coefficients

also

here is a really slow way to do it

you know the moles of gas increased

so Delta S is positive

so its B or D

then just do the units digit to see which one match up

6 0

3 years ago