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Lady_Fox [76]
3 years ago
12

A baseball pitcher throws a baseball with a speed of 42 m/s . In throwing the baseball, the pitcher accelerates it through a dis

placement of about 3.5 m, from behind the body to the point where it is released.
Physics
1 answer:
andrew-mc [135]3 years ago
8 0

Answer:

a = 252 m / s²

Explanation:

The initial speed Vο = 0

The speed of baseball with witch it is thrown  Vf = 42 m/s

Displacement covered = 3.5 m

Hence acceleration will be constant at this moment, so as per the equation of constant acceleration : ( Vf² - Vο² ) / 2d = a

                                                            a = 252 m / s²

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Answer:

F = 2.69 10⁻³ m   [ N]

Explanation:

This exercise asks to calculate the gravitational field of the Earth on the lunar surface, let's use the universal gravitation law

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         F = (G M / r²) m

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laiz [17]

Answer:

608.4m/s

Explanation:

We are given that

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Mass of jet,m=4800 kg

Total mass=M+m=1200+4800=6000 kg

We have to find the final velocity of the two objects after the collision.

The collision is inelastic .

By using law of conservation of momentum

Mu+mu'=(m+M)v

Using the formula

1200\times 322+4800\times 680=6000v

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