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RideAnS [48]
4 years ago
5

If a fire wipes out all of the available nutrients for a deer population living in a forest,

Chemistry
2 answers:
Mazyrski [523]4 years ago
5 0

b

Oh yea Big Brain Time

const2013 [10]4 years ago
5 0

Answer: Option B

Explanation:

The fire wipes out all the available food in the forest then the deer population will be reduced. This is because there will be no food available to the deer as a source of energy.

The organism eats food to get energy and survive and failing to do so will kill the organism.

According to the food chain the organism in one tropic level will affect the life of another level. So, loss of nutrient will kill deer.

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4 0
3 years ago
With what compound will nh3 experience only dispersion intermolecular forces? with what compound will nh3 experience only disper
Burka [1]
Answer is: ammonia experience only dispersion intermolecular forces with BF₃ (boron trifluoride) because BF₃ is only nonpolar molecule (vectors of dipole moments cansel each other, dipole moment is zero).
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3 years ago
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6. 5.50 x 10- molecules of carbon dioxide to moles.
sergeinik [125]
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4 0
3 years ago
How many grams of carbon are contained in 2.25 g of potassium carbonate, K2CO3
romanna [79]

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

<h3>Molecular mass of potassium carbonate</h3>

The molecular mass of potassium carbonate, K₂CO₃ is calculated as follows;

M = K₂CO₃

M = (39 x 2) + (12) + (16 x 3)

M = 138 g

mass of carbon in potassium carbonate, K₂CO₃ is = 12 g

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is calculated as follows;

138 g ------------ 12 g of carbon

2.25 g ------------ ?

= (2.25 x 12) / 138

= 0.196 g

Thus, the mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

Learn more about potassium carbonate here: brainly.com/question/27514966

#SPJ1

5 0
2 years ago
100cm³of a solution of potassium hydroxide contains 0.56g of the dissolved solute. What is the molar concentration of this solut
s2008m [1.1K]

Answer:

[KOH] = 0.10M in KOH

Explanation:

Molar Concentration [M] = moles solute/volume solution in liters

moles KOH = 0.56g/56g/mole = 0.01mole

Volume of solution = 100cm³ = 100ml = 0.10 liter

[KOH] = 0.01 mole KOH / 0.10 liter solution = 0.10M in KOH

5 0
3 years ago
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