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denis-greek [22]
3 years ago
8

The red stripes shown in the formation above are a result of ________ deposits.

Physics
1 answer:
lina2011 [118]3 years ago
5 0

C iron oxide hope this helps

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The length of an aluminum wire is quadrupled and the radius is doubled. By which factor does the resistance change?
erik [133]
The resistance of a conductive wire is given by:
R= \frac{\rho L}{A}
where
\rho is the material resistivity
L is the wire length
A is the cross-sectional area of the wire

The length of the wire is quadrupled, so if we call L the original length and L' the new length, we can write 
L'=4 L

Similarly, the radius of the wire is doubled (r'=2r), so the new area is
A'= \pi (r')^2 = \pi (2r)^2 = 4 \pi r^2 = 4A

And if we substitute into the equation, we find that the new resistance of the wire is
R'= \frac{\rho L'}{A'}= \frac{\rho (4L)}{4 A'}  =  \frac{\rho L}{A}=R
Therefore, R=R': this means that the resistance of the wire did not change.
7 0
2 years ago
A baseball is given an initial velocity with magnitude v at the angle beta above the surface of an incline which in turn incline
lakkis [162]

Explanation:

The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 ⁡ θ i 2 g .

8 0
2 years ago
A person jumping out of speeding bus goes forward why?​
kobusy [5.1K]

Answer:

gravity because its gravity and you fall and die

4 0
2 years ago
A 210 Ohm resistor uses 9.28 W of
IgorLugansk [536]
  • Resistance=R=210Ohm
  • Power=9.28W=P

Current=I

\boxed{\sf P=I^2R}

\\ \sf\longmapsto I^2=\dfrac{P}{R}

\\ \sf\longmapsto I^2=\dfrac{9.28}{210}

\\ \sf\longmapsto I^2\approx0.04

\\ \sf\longmapsto I\approx\sqrt{0.04}

\\ \sf\longmapsto I\approx\sqrt{\dfrac{4}{100}}

\\ \sf\longmapsto I\approx\dfrac{\sqrt{4}}{\sqrt{100}}

\\ \sf\longmapsto I\approx\dfrac{2}{10}

\\ \sf\longmapsto I\approx0.2A

4 0
2 years ago
Question 6 (15 points)
aleksandrvk [35]

Answer:

that would be newtons 3rd law

Explanation:

because its how it is

3 0
3 years ago
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