We have volume of gasoline = 14.0 gallon
Time taken to fill automobile tank = 1.50 minutes
So volume rate = 14.0 gallon/1.50 minutes = 9.33 gallon/ minute
We have density of gasoline = 0.77 kg/L = 6.073 lb/US gal
Mass rate = Density * Volume rate
= 9.33 gallon/ minute*6.073 lb/US gal = 56.68 lb/min
So mass flow rate delivered by the gasoline pump in lbm/min = 56.68
2nd and third laws of energy
Warm water<span> has more energy </span><span>than cold water</span>
Vi = 2m/s
a= 4.5 m/s
d= 340 m
vf= ?
use this equation ... vf^2=vi<span>^2+2ad
you should get vf = 55.3
hope this helps </span>