Answer:
Explanation:
Given 2H₃PO₄ + 3Ca ⇒ 3H₂ + Ca₃(PO₄)₂
27.4g
=(27.4g/98g/mol)
= 0.280 mole H₃PO₄ used
Ca Used:
Rxn Ratio H₃PO₄ : Ca => 2:3
∴ moles Ca used = 3/2(0.280) mole Ca =0.420 mole Ca
grams Ca used = 0.420 mole Ca x 40 g/mole = 16.8 grams Ca used
Grams H₂ Produced:
Rxn Ratio H₃PO₄ : H₂ => 2:3 => moles H₂ produced = 3/2(0.28 mole H₂) = 0.420 mole H₂ = (0.420 mole H₂ x 2.02 g/mole) = 0.8484 grams H₂(g) Produced.
Moles Ca₃(PO₄)₂ Produced:
FWt Ca₃(PO₄)₂ = 310 g/mole
Rxn Ratio H₃PO₄ : Ca₃(PO₄)₂ => 2:1
∴moles Ca₃(PO₄)₂ Produced = 1/2(moles H₃PO₄ used)
= 1/2(0.28 mole) = 0.14 mole Ca₃(PO₄)₂
If you want grams Ca₃(PO₄)₂, multiply moles Ca₃(PO₄)₂ by formula weight.
