(Missing in your question ):
we have the following reaction:
A(aq) ↔ 2 B(aq)
and Kc = 7.02 x 10^-6 at 500K
So at equilibrium,
Kc = [Products] / [ reactants]
= [B]^2 / [A]
we have [A] = 3.3 m and Kc is given= 7.02 x10^-6
by substitution:
7.02x10^-6 = [B]^2 / 3.3
∴[B]^2 = 2.3 x 10^-5
∴[B] = 0.005 m
Answer:
m = 17
Explanation:
From the question we were given that
Triangle WZY is bisected by ZX; ZW = ZY
∠YXZ = (6m – 12)°
Based on the characteristics of the triangle, we see that triangle WYZ is an isosceles triangle (that is, triangle WXZ is equal to triangle YXZ)
<YXZ = <WXZ = 90°
Using ∠YXZ = (6m – 12)°
We have:
(6m – 12)° = 90°
6m = 90 + 12 ⇒ 6m = 102
m = 102 ÷ 6 = 17
m = <u>17</u>
<u>We therefore see that m is equal to 17</u>
Answer:
B) A piece of metal in water and produces spark and gas
Answer: Activation energy
Explanation:
In a chemical reaction, the reactants contains particles which must collide in order for a reaction to occur. The rate of reaction depends on the frequency of effective collision between the reacting particles. Effective collision are those that result in reactions, which when they occur the colliding particles become activated with increased kinetic energy.
This energy must exceed a particular energy barrier for a particular reaction if the reaction must take place. This energy barrier that must be overcome before a reaction takes place is known as the ACTIVATION ENERGY.
To explain further, when two particles or molecules A and B come in contact with each other, for a reaction to take place, they must collide with a sufficient force to break the bond that exists between them. The minimum combined kinetic energy these reactant particles must possess in order for their collision to result in a reaction is called the activation energy.
Assuming the E you are referring to is Internal Energy, <span>which refers to the total amount of the kinetic and potential </span>energies<span> of the particles that form your system. The common units for this internal energy are kcal/mole, and kJ/mol.</span>