I am pretty sure that the statement which is true is A. a molecule having a covalent bond can be ionic. I choose this option because you usually ca see how electons of polyatomic ions are being covalenr and gain or loose ionic electrons in order to accomplish the octet.<span>
</span>Do hope you find it helpful! Regards.
Answer:
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O
2NO(g) + O₂(g) → 2 NO₂
Explanation:
First of all, we need to consider the reaction for production of ammonia. In this reaction we have as reactants, nitrogen and hydroge.
3H₂ (g) + N₂(g) → 2NH₃ (g)
Afterwards, ammonia reacts to oxygen, to produce NO and H₂O
The equation for the process will be:
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O
Then, we take the nitric oxide to make it react, to produce NO₂, in order to produce nitric acid, for the final reaction:
2NO(g) + O₂(g) → 2 NO₂
3NO₂(g) + H₂O(g) → 2 HNO₃ (g) + NO(g)
D) <span> Electrical energy accelerates the electrons in the neon gas. The gas ionizes and becomes plasma, containing both positive and negative ions.</span>
Answer:
An inverse relationship can neither be represented by a straight line nor by a bar chart. But it can be represented by "xy = k"
Explanation:
Inverse relation is used for the values which are inversely related to each other. For example: Let suppose you have a value x and y. Then an increase in the value of x will result in the decrease of value y. Mathematically it is represented as,
x ∝ 1 / y
Where;
∝ = proportionality
Replacing the proportionality sign by a constant value "k" the relation becomes,
x = k / y
Solving for k,
x y = k
Conclusion:
Hence, an inverse relationship can be represented by "xy = k"
The oxidation half-reaction occurs at one electrode (the anode), and the reduction half-reaction occurs at the other (the cathode). When the circuit is closed, electrons flow from the anodeto the cathode.
