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ratelena [41]
3 years ago
13

Which of the following is the best paraphrasing of the Heisenberg uncertainty principle? Which of the following is the best para

phrasing of the Heisenberg uncertainty principle? Only if you know the exact position of a particle can you know the exact momentum of the particle. The more precisely you know the position of a particle, the less well you can know the momentum of the particle. How well you can determine the position and momentum of a particle depends on the particle's quantum numbers. The larger the momentum of a particle, the smaller the position of the particle. The better you know the position of a particle, the better you can know the momentum of the particle.
Physics
1 answer:
weqwewe [10]3 years ago
4 0
<h2>Answer:The more precisely you know the position of a particle, the less well you can know the momentum of the particle</h2>

The Heisenberg uncertainty principle was enunciated in 1927. It postulates that the fact that each particle has a wave associated with it, imposes <u>restrictions on the ability to determine its position and speed at the same time. </u>

In other words:  

It is impossible to measure simultaneously (according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle.  

<h2>So, the greater certainty is seeked in determining the position of a particle, the less is known its linear momentum and, therefore, its mass and velocity.  </h2><h2 />

In fact, even with the most precise devices, the uncertainty in the measurement continues to exist.  Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.

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A ball is thrown against a wall and bounces back toward the thrower with the same speed as it had before hitting the wall. Does
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A) Although the speed is the same, the direction has changed. Therefore, the velocity has changed.

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3 years ago
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3 years ago
a train car of mass 444 kg moving at 5 m/s bounces into another car on the same tracks of mass 344 king. of the second car was m
Kamila [148]

Answer:

3.7 m/s

Explanation:

M = 444 kg

U = 5 m/s

m = 344 kg

u = - 5 m/s

Let the velocity of train is V and the car s v after the collision.

As the collision is elastic

By use of conservation of momentum

MU + mu = MV + mv

444 x 5 - 344 x 5 = 444 V + 344 v

500 = 444 V + 344 v

125 = 111 V + 86 v .... (1)

By using the formula of coefficient of restitution ( e = 1 for elastic collision)

e = \frac{V-v}{u-U}

-5 - 5 = V - v

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v = V + 10

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3 years ago
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