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vfiekz [6]
3 years ago
12

Before 2006, while Pluto was still considered a planet, people used this saying to remember the nine planet names: "My very exce

llent mother just sent us nine pizzas." Come up with a new sentence to help remember the eight planet names, in order.
Physics
1 answer:
Serjik [45]3 years ago
4 0

Answer:

Mother's Visit Evoked My Junior Sister's Unseen Niceness

Explanation:

Mother's  - M - stands for Mercury

Visit          - V - Stands for Venus

Evoked     - E - Stands for Earth

My             - M - stands for Mars

Junior         -J - stands for Jupiter

Sister's       -S- Stands for Saturn

Unseen      -U - stands for Uranus

Niceness   - S- stands for Neptune

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Steel ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.45 m.
Amiraneli [1.4K]

Answer:

Vb= 5.42 m/s

Vc= 5.33 m/s

a=-1125\ m/s^2

Δ L= 0.43 mm

Explanation:

a)  A to B

Initial velocity Va = 0 m/s

As we know that

V^2=U^2+2aS

V_b^2=2\times 9.81\times 1.5

Vb= 5.42 m/s

b)

C to D

Vd= 0 m/s

0^2=V_c^2-2\times 9.81\times 1.45

Vc= 5.33 m/s

c)

Here

Vb= 5.42 m/s

Vc= 5.33 m/s

We know that

Acceleration is the rate of change of velocity

a=\dfrac{V_c-V_b}{t}

a=\dfrac{5.33-5.42}{8\times 10^{-5}}

a=-1125\ m/s^2

d)

Now length compressed given as

V_c^2=V_b^2+2a\Delta L

5.33^2=5.42^2-2\times 1125\times  \Delta L

  Δ L= 0.43 mm

3 0
4 years ago
What is the most likely reason that horses and mountain goats have hooves?
Nastasia [14]

Answer:

They have homologous structures because they have a common ancestor.

Explanation:

6 0
3 years ago
Read 2 more answers
A 6.50 meter high cylinder is filled with alcohol(density =806 kg/m^3). What is the pressure at the bottom of the cylinder?
makvit [3.9K]

Answer:

152642.2

Explanation:

the pressure at the bottom of the cylinder is

P = Po + rho gh

=101300+806(9.8)(6.5)

=152642.2 Pa

3 0
3 years ago
PLX HELP
Gnesinka [82]

The answer to this question is A.

3 0
4 years ago
Read 2 more answers
A 10-g bullet moving horizontally with a speed of 2.0 km/s strikes and passes through a 4.0-kg block moving with a speed of 4.2
SVEN [57.7K]

Answer:

K=512J

Explanation:

Since the surface is frictionless, momentum will be conserved. If the bullet of mass m_1 has an initial velocity v_{1i} and a final velocity v_{1f} and the block of mass m_2 has an initial velocity v_{2i} and a final velocity v_{2f} then the initial and final momentum of the system will be:

p_i=m_1v_{1i}+m_2v_{2i}

p_f=m_1v_{1f}+m_2v_{2f}

Since momentum is conserved, p_i=p_f, which means:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}

We know that the block is brought to rest by the collision, which means v_{2f}=0m/s and leaves us with:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}

which is the same as:

v_{1f}=\frac{m_1v_{1i}+m_2v_{2i}}{m_1}

Considering the direction the bullet moves initially as the positive one, and writing in S.I., this gives us:

v_{1f}=\frac{(0.01kg)(2000m/s)+(4kg)(-4.2m/s)}{0.01kg}=320m/s

So kinetic energy of the bullet as it emerges from the block will be:

K=\frac{mv^2}{2}=\frac{(0.01kg)(320m/s)^2}{2}=512J

6 0
4 years ago
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