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topjm [15]
3 years ago
10

The experiment where the factors being tested are not applied. It allows scientists to set a baseline to compare the experimenta

l groups that do have factors applied to them.
Test variable (independent variable):
Outcome variable (dependent variable):
Control group:
Chemistry
1 answer:
olasank [31]3 years ago
5 0

Answer:

An experiment is a research method performed within a completely controlled environment that uses groups of individuals ( subjects), one of which the factors being tested are not spplied on, an independent factor of the hypothesys ( to be tested ), for example the resilience of a group of teenagers) and a dependant factor that is applied to check how it varyes depending on the tested factor ( for example, the most challanging experience of their generation)

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Will iron fillings and lead oxide powder react
Andru [333]

Answer:

Yes they woll react.

Explanation:

Ferous oxide and zinc will be product.

8 0
4 years ago
20pts help plz
zepelin [54]

It is C

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6 0
3 years ago
Read 2 more answers
A combustion reaction occurs between one molecule of methane (CH4) and two molecules of oxygen (O,)
faltersainse [42]

Answer:

D

Explanation:

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8 0
2 years ago
How much oxygen will contain the same number of atoms as the number of molecules in 73 g of HCI?​
expeople1 [14]

Answer:

64g of O2.

Explanation:

We'll begin by calculating the number of molecules in 73g if HCl.

This is illustrated below:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of HCl also contains 6.02×10²³ molecules

1 mole of HCl = 1 + 35.5 = 36.5g

Thus, if 36.5g of HCl contains 6.02×10²³ molecules, then 73g of HCl will contain = (73 x 6.02×10²³)/36.5 = 1.204×10²⁴ molecules.

Therefore, 73g of HCl will contains 1.204×10²⁴ molecules.

Now, we shall determine the mass of oxygen that will contain 1.204×10²⁴ molecules.

This can be obtained as follow:

1 mole of O2 = 16x2 = 32g

32g of O2 contains 6.02×10²³ molecules.

Therefore, Xg of O2 will contain 1.204×10²⁴ molecules i.e

Xg of O2 = (32 x 1.204×10²⁴)/6.02×10²³

Xg of O2 = 64g

Therefore, 64g of O2 will contain the same number of molecules (i.e 1.204×10²⁴ molecules) in 73g of HCl.

5 0
3 years ago
PLEASE HELP ME I NEED TO SUBMIT RIGHT NOW
sasho [114]

Answer:  number of protons?

Or  different atomic weight.

I DONT KNOW ;';

5 0
3 years ago
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