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stich3 [128]
4 years ago
12

A car uses 2500 joules in 25 seconds. find power

Physics
2 answers:
irina1246 [14]4 years ago
7 0

Answer:

100 W

Explanation:

The power can be defined as energy change / time taken

Or

Energy used/time taken

So in this case you get,

Power = 2500/25 = 100 W

Katena32 [7]4 years ago
5 0

Answer:

power = 100 watts

Explanation:

Power is said to be the rate at which work is done. Power is the work done or energy used per unit time. Mathematically, it can be defined as the work done per unit time.

Power = work/time

Power = w/t

Work  done is measured in joules and time is measured in seconds.

Power is measured in joules per seconds or watts.

power = w/t

w = 2500 joules

t = 25 seconds

power =  2500/25

power = 100 watts

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Answer:

solution

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3 years ago
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By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what
Vinil7 [7]

Explanation:

1. Mass of the proton, m_p=1.67\times 10^{-27}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}

V=\dfrac{h^2}{2q_pm_p\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}

V = 45.83 volts

2. Mass of the electron, m_p=9.1\times 10^{-31}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}

V=\dfrac{h^2}{2q_em_e\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}

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7 0
4 years ago
Nuclear sizes are expressed in a unit named
o-na [289]

Answer:

Answer is A) Fermi

Explanation:

Fermi is the expressive unit for nuclear sizes. Fermi = 10^-15 meter.

4 0
3 years ago
A smooth circular hoop with a radius of 0.800 m is placed flat on the floor. A 0.300-kg particle slides around the inside edge o
Marrrta [24]

Answer:

a)11.25 J

b)Number of revolution = 1

Explanation:

Given that

Radius ,r= 0.8 m

m= 0.3 kg

Initial speed ,u= 10 m/s

final speed ,v= 5 m/s

a)

Initial energy

KE_i=\dfrac{1}{2}mu^2

KE_i=\dfrac{1}{2}0.3\times 10^2

KEi= 15 J

Final kinetic energy

KE_f=\dfrac{1}{2}mv^2

KE_f=\dfrac{1}{2}0.3\times 5^2

KEf=3.75 J

The  energy transformed from mechanical to internal = 15 - 3.75 J = 11.25 J

b)

The minimum value to complete the circular arc

 V=\sqrt{r.g}

Now by putting the values

V=\sqrt{0.8\times 10}

V= 2.82 m/s

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KE=\dfrac{1}{2}mV^2

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ΔKE= KEi - KE

ΔKE= 15- 1.19 J

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The minimum energy required to complete 2 revolutions = 2 x 11.25 J

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Here 22.5 J is greater than 13.8 J.So the particle will complete only one revolution.

Number of revolution = 1

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3 years ago
Rita conducts an experiment on how the amount of precipitation each fall affects
hodyreva [135]

Answer:

Explanation:

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5 0
3 years ago
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