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3 years ago

A car uses 2500 joules in 25 seconds. find power

Physics

2 answers:

irina1246 [14]3 years ago

7 0

Answer:

100 W

Explanation:

The power can be defined as energy change / time taken

Energy used/time taken

So in this case you get,

Power = 2500/25 = 100 W

Katena32 [7]3 years ago

5 0

Answer:

power = 100 watts

Explanation:

Power is said to be the rate at which work is done. Power is the work done or energy used per unit time. Mathematically, it can be defined as the work done per unit time.

Power = work/time

Power = w/t

Work done is measured in joules and time is measured in seconds.

Power is measured in joules per seconds or watts.

power = w/t

w = 2500 joules

t = 25 seconds

power = 2500/25

power = 100 watts

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timama [110]

Answer:

K = 80.75 MeV

Explanation:

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$E_{ph} = E_{p} + E_{ap} = E_{0p} + K_{p} + E_{0ap} + K_{ap} = m_{0p}c^{2} + K_{p} + m_{0ap}c^{2} + K_{ap}$

<em>where $E_{ph}$ : is the photon energy, $E_{0p} and E_{0ap}$ : are the rest energies of the proton and the antiproton, respectively, equals to m₀c², $K_{p} and K_{ap}$ : are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.</em>

Therefore the kinetic energy of the antiproton is:

$K_{ap} = E_{ph} - m_{0p}c^{2} - K_{p} - m_{0ap}c^{2}$

<u>The proton mass is equal to the antiproton mass, so</u>:

$K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV$

$K_{ap} = 80.75 MeV$

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

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