N= m/v n=0.077/.200 = 0.385
Answer:
n=N/Na
n = \frac{8.23 \times {10}^{22} }{6.02 \times {10}^{23} } = 0.1367 \: mol
answer: 0.14 mol
Explanation:
Answer:
The answer to your question is: letter c (96%)
Explanation:
Indium -113 (112-9040580 amu) ₁₁₃In
Indium-115 (114.9038780 amu) ₁₁₅In
Atomic mass of Indium is 114.82 amu ₁₁₄.₈₂In
Formula
Atomic mass = m₁(%₁) +m₂(%₂) / 100
%₁ = x I established this is an equation
%₂ = 100 - x
Substituting values
114.82 = 112.8040x + 114.9039(100-x) /100 and know we expand and simplify
114.82 = 112.8040x + 11490.39 - 114.9039x /100
11482 = 112.8040x -114.9039x +11490.39
11482 - 11490.39 = 112.8040x -114.9039x
-8.39 = -2.099x
x = 3.99
Then % of Indium-115 = 100 - 3.99 = 96
We have as a reagent a salt, lead nitrate (Pb(NO3)2), and an unknown solution that gives us as a product lead chloride (PbCl2). That is, the solution must contain chlorine.
If a chlorine solution is used we will have the following reaction:
So, with a chlorine solution, we will have a white precipitate of lead chloride.
Answer:
Density is 6.16g/L
Explanation:
<em>... at exactly -15°C and exactly 1atm...</em>
<em />
Using general gas law:
PV = nRT
We can find density (Ratio of mass and volume) in an ideal gas as follows:
P/RT = n/V
<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>
n*MW = m
n = m/MW
P/RT = m/V*MW
P*MW/RT = m/V
<em>Where P is pressure: 1atm;</em>
<em>MW of chlorine pentafluoride: 130.445g/mol</em>
<em>R is gas constant: 0.082atmL/molK</em>
<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>
<em />
Replacing:
P*MW/RT = m/V
1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V
6.16g/L = m/V
<h3>Density of the gas is 6.16g/L</h3>
<em> </em>
