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tankabanditka [31]
3 years ago
9

The pathologic changes that occur in the development of coronary atherosclerotic lesions include call damage resulting from whic

h of the following? (Select all that apply):
1. a decrease in smooth muscle cells2. a chronic calcium buildup3. the effects of oxidized lipids4. an inflammatory response5. the formation of plaques
Physics
1 answer:
ale4655 [162]3 years ago
4 0

Answer:

3 effect of oxidized lipids

4 an inflammatory response

5 the formation of plaques

Explanation:

Destruction of cells due to oxidation of lipids whereby free radicals steal electrons in cell membrane.

This occurs when tissues get injured by trauma, bacteria or toxins, thereby causing damages cells to release chemicals like histamine, brakykinn that cause vessels to leak fluid into the injured tissues causing swelling.

-plaques are regions of destroyed cells which are visible structures formed inside a cell culture.

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A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn
KatRina [158]

Answer:

15.99861 seconds

1865.58658 Joules

Explanation:

\alpha = Angular acceleration

\theta = Angle of rotation

I = Moment of inertia of disc = 0.031 kgm²

t = Time taken

Initial angular speed

\omega_i=3313\frac{2\pi}{60}\\\Rightarrow \omega_i=346.93\ rad/s

Final angular velocity

\omega_f=0.75\times \omega_i\\\Rightarrow \omega_f=0.75\times 346.93\\\Rightarrow 260.19\ rad/s

From the equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{260.19-346.93}{4}\\\Rightarrow \alpha=-21.685\ rad/s^2

\omega_f=\omega_i+\alpha t\\\Rightarrow t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{0-346.93}{-21.685}\\\Rightarrow t=15.99861\ s

Time taken by the turntable to slow down is 15.99861 seconds

Rotational energy is given by

K=\frac{1}{2}I\omega_i^2\\\Rightarrow K=\frac{1}{2}\times 0.031\times 346.93^2\\\Rightarrow K=1865.58658\ J

The work has to be done on the turntable to bring it to rest is 1865.58658 Joules

7 0
4 years ago
4. A 15 V battery is connected to three capacitors in series. The capacitors have the following
Anastaziya [24]
Vp = Vs 14.o V battery 3.96 ûF
5 0
4 years ago
A 47.5-turn circular coil of radius 5.25 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0
Free_Kalibri [48]

Answer:

Torque, 5.91\times 10^{-3}\ N-m

Explanation:

Given that,

The number of turns in the coil, N = 47.5

Radius of the coil, r = 5.25 cm

Uniform magnetic field, B = 0.535 T

Current in the coil, I = 26.9 mA

The magnitude of the maximum possible torque exerted on the coil isg given by :

\tau=NIAB\\\\\tau=47.5\times 26.9\times 10^{-3}\times \pi (5.25\times 10^{-2})^2\times 0.535 \\\\\tau=0.00591\ N-m\\\\\tau=5.91\times 10^{-3}\ N-m

So, the magnitude of the maximum possible torque exerted on the coil is 5.91\times 10^{-3}\ N-m.

3 0
3 years ago
Suppose you toss a tennis ball upward.a) Does the kinetic energy of the ball increase or decrease as it moves higher?b) What hap
Lilit [14]

Answer:

a) No. The kinetic energy of the ball decreases.

b) The potential energy of the ball increases.

c) The ball would go half of the original distance.

Explanation:

a) The kinetic energy would be converted to potential energy as the ball goes higher. Since the total mechanical energy is conserved, the kinetic energy would decrease.

b) The potential energy of the ball would increase. Since the total mechanical energy of the ball is conserved, the ball would lose speed, and therefore kinetic energy. In order to compensate the loss of kinetic energy, the ball would gain potential energy as it goes higher.

c) The relation of the energy and mass is as follows:

K = \frac{1}{2}mv^2\\U = mgh

According to the energy conservation

K_1 + U_1 = K_2 + U_2\\\frac{1}{2}mv^2 + 0 = 0 + mgh\\\frac{1}{2}v^2 = gh

The maximum height that the ball reaches is proportional to the initial velocity. If the ball would be imparted with the same amount of energy, its final potential energy would be the same. However, in order to have the same potential energy (mgh), its height would be half of the original case.

mgh = (2m)g(\frac{h}{2})

7 0
3 years ago
When the speed of electrons striking the anode of an x-ray tube increases, the _____ of the emitted x-rays increases.
Yuki888 [10]
Cathody Ray electrons striking the anode of an x-ray tube increases
5 0
4 years ago
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