How to solve arctan[tan(7pi /4)] ...?

1 answer:

7 0

Well,
arctan is a bijection from R into (-pi/2 , pi/2)*and
pi is a period of tangent function:
so
as we have : tan(7pi/4) = tan(pi - pi/4) = - tan(pi/4)
we finally get :

<span>arctan(tan(7pi/4)) = artan(tan(- pi/4)) = - pi/4
</span>

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<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

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