Question

A student standing in a canyon yells "echo", and her voice produces a sound wave of frequency of f = 0.61 kHz. The echo takes t = 3.9 s to return to the student. Assume the speed of sound through the atmosphere at this location is v = 322 m/s.

Answer 1

Answer:

$d=627.9\ m$  is the distance from the obstacle of reflection.

wavelength $\lamb=0.5279\ m$

Explanation:

Given that:

• frequency of sound, $f=610\ Hz$

• time taken for the echo to be heard, $t=3.9\ s$

• speed of sound, $v=322\ m.s^{-1}$

We know,

$\rm distance = speed \times time$

During an echo the sound travels the same distance back and forth.

$2d=v.t$

$2d=322\times 3.9$

$d=627.9\ m$  is the distance from the obstacle of reflection.

Now the wavelength of sound waves:

$\lambda=\frac{v}{f}$

$\lambda=\frac{322}{610}$

$\lamb=0.5279\ m$