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FrozenT [24]
3 years ago
6

Objects are recognized by their 1) shape 2) properties 3) odor 4)color

Chemistry
1 answer:
8_murik_8 [283]3 years ago
3 0
I would say properties.
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1. What process occurs along transform fault plate boundary?​
Lana71 [14]

Answer:

hope it helps...

Explanation:

Along the third type of plate boundary, two plates move laterally and pass each other along giant fractures in Earth's crust. Transform faults are so named because they are linked to other types of plate boundaries. The majority of transform faults link the offset segments of oceanic ridges.

7 0
3 years ago
Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is how many grams/cub
emmasim [6.3K]
This is asking for the absolute humidity. So if the relative humidity is 65 % and the air temperature is 30 then we need to have in mind the barometric pressure which will be 760. The humidity in the air will be 0.020 kg/m3. In order to know this we calculate it eith the mass of water vapour in a unit volume of air. This is a measure of the actual water vapour content of the air. the for mula would go like this: AH = Mv / V. 
5 0
3 years ago
An athlete can run 4 m/s. How far can she run in 3 minutes?<br>​
shutvik [7]

Answer:

720

Explanation:

4 m/s

<u>60</u> seconds

                            = 180 seconds

<u>3</u> minutes

<u>4</u> m/s

                             = <u>720 m/s</u>

<u>180</u> seconds

5 0
3 years ago
A sample of gas occupies 1.2 L at 12.0oC. Assuming pressure remains the same, what would be the volume (in L) of this gas at 67o
Levart [38]

Answer:

e.

6.7

hope it help

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4 0
3 years ago
Determine the equilibrium constant, Keq, at 25°C for the reaction
adelina 88 [10]

Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

3 0
3 years ago
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