<u>Answer:</u>
15.97 N force is tending to pull Rover forward
<u>Explanation:</u>
The woman pulls on the leash with a force of 20.0 N at an angle of 37° above the horizontal. The arrangement is shown in the given figure,
We nee to find the pulling force P. The 20.0 N force has two components, 20.0 cos 37 in horizontal direction and 20.0 sin 37 in vertical direction.
The horizontal component is equal to pulling force P, which will pull Rover forward/
So, P = 20.0 cos 37 = 15.97 N
15.97 N force is tending to pull Rover forward.
Answer:
A = (27.95 N, 21 N)
Explanation:
The polar co-ordinates are given as:
(r,θ) = (35 N, 37°)
Now, to convert this into polar co-ordinates (x, y), we will use following relations:
r² = x² + y²
(35)² = x² + y²
1225 = x² + y² ----------- equation (1)
and
tan θ = y/x
tan 37° = y/x
y = 0.753 x ------------------- equation (2)
Substituting this value in equation (1):
1225 = x² + (0.753 x)²
1225 = 1.567 x²
x² = 1225/1.567
x = √781.32
x = 27.95 N
using this value in equation (2)
y = (0.753)(27.95 N)
y = 21 N
Therefore, the vector can be represented in polar co-ordinates as:
<u>A = (27.95 N, 21 N)</u>
Answer:
A. Drag
Explanation:
This is because, since friction tends to oppose the motion of an object, and drag affects an object moving in a fluid, the more the friction, the more the drag on the object.
Hello there!
Your question can be answered using the
Newton's Secon Law of Motion:
This Law says that the forces on an object are equal to the product of its mass (m) and acceleration (a):

If we clear this equation for acceleration, we'll see that:

So, studying this equation, we'll see that acceleration is inversely proportional to mass, thus, assuming that the force remains constant,
doubling the mass will decrease the acceleration of the object by half.