Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer:
the true stress for the second material is 629.19MPa
Explanation:
given for material 1,
l₀ = 48mm
l₁ = 53.5m
e = change in length = 53.5 - 48 = 5.5mm
true stress = 368MPa
strain = Δlength/original length = e/l₀
stress = force / area = F/A
young modulus, E = stress/strain = Fl₀/Ae
E = stress * l₀/e
E = 368 * 48/5.5 = 368 * 8.73 = 3212.64
for material 2 of the same properties, meaning E for both material is the same, therefore,
l₀ =48, l₁=57.4, e = 57.4-48
e=9.4mm
E = stress * l₀/e
3212.64 = stress * (48/9.4)
3212.64 = 5.106 * stress
stress for 3212.64/5.106 = 629.189MPa
the true stress for the second material is 629.19MPa
Answer:
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Answer:
C.
Explanation:
The question states that x has is value in between and including 1.9 and 2.1. So the number is greater than or equal to 1.9 but less than or equal to 2.1.
In option A this means that the value of x is greater than or equal to 2.1 which does not satisfy the condition mentioned in the question
In option D is greater than or equal to 2.1 but less than or equal to 1.9 which does not satisfy the condition mentioned in the question.
In option C is greater than or equal to 1.9 and less than or equal to 2.1 which does satisfy the condition mentioned in the question.
So, option C is correct.
Answer:
Amplifier gain is equal to 10.67.
Explanation:
Voltage gain of an amplifier can be expressed as this equation:
A_v = (V_output) / (V_input)
Where A_v is the gain, V_output is the output voltage, and V_input is the input voltage.
For this we will solve:
A_v = 128 mV / 12 mV
A_v = 10.67
So the amplifier's gain is 10.67.
Cheers.