There's no such thing as "stationary in space". But if the distance
between the Earth and some stars is not changing, then (A) w<span>avelengths
measured here would match the actual wavelengths emitted from these
stars. </span><span>
</span><span>If a star is moving toward us in space, then (A) Wavelengths measured
would be shorter than the actual wavelengths emitted from that star.
</span>In order to decide what's actually happening, and how that star is moving,
the trick is: How do we know the actual wavelengths the star emitted ?
The apparent shift <span>is the apparent in the position of an object when viewed from two locations.
Hope this helps :)</span>
<span>When n=4 subdivisions distance traveled = 40 X 12 = 480
When n=2 subdivisions distance traveled = 30 X 6 = 180
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
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True IF the engine is 25% efficient. False otherwise.
Using the formula: ΔY = V₀y * t + (1/2) * ay * t²
Solve for time and get: 1.968s
Then use: v = d/t in the x-direction and get: d = 3.936
