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Lubov Fominskaja [6]
3 years ago
6

Which statement best describes frustration?

Physics
1 answer:
wlad13 [49]3 years ago
5 0
C. when you can't achieve your goal due to events beyond your control
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Which is capeble of housing astronaughts while they conduct reasearch
dusya [7]

Answer:

2

Explanation:

2

5 0
3 years ago
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when a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g÷2 (gravity over 2) show that : dens
Mamont248 [21]

The density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.

<h3>What is the relationship between acceleration and density?</h3>

For a solid falling through a viscous fluid, the acceleration of the object decreases until it attains terminal velocity.

The acceleration of the body increases with increase in density of the solid.

When density of solid = density of liquid, acceleration a = g

When density of solid = 2 × density of the liquid, acceleration a = g/2.

Therefore, the density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.

Learn more about density and acceleration at: brainly.com/question/1156422

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3 0
2 years ago
Where does groundwater come from?
jek_recluse [69]
Groundwater is the water found underground in the cracks and spaces in soil, sand and rock. It is stored in and moves slowly through geologic formations of soil, sand and rocks called aquifers.


Hope this helps.


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4 0
3 years ago
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A student sees a newspaper ad for an apartment that has 1330 square feet (ft^2) or floor space. How many square meters of area a
Natasha2012 [34]
<span>=1330 ft^2 x (1m^2/3.25 ft^2)
=124 m^2

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6 0
3 years ago
A student removes a 10.5 kg stereo amplifier from a shelf that is 1.82 m high. The amplifier is lowered at a constant speed to a
Nonamiya [84]

Answer:

(a) the work done by the student is 110.1 J

(b) The gravitational force that acts on the amplifier is 102.9 N

Explanation:

Given;

mass of the amplifier, m = 10.5 kg

initial position of the amplifier, x₀ = 1.82 m

final position of the amplifier, x₁ =0.75 m

The dispalcement of the amplifier Δx = x₁ - x₀ = 1.82 m - 0.75 m = 1.07 m

(b) The gravitational force that acts on the amplifier;

F = mg

F = 10.5 x 9.8

F = 102.9 N

(a) the work done by the student is calculated as;

W = FΔx

W = 102.9 x 1.07

W = 110.1 J

7 0
3 years ago
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