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wlad13 [49]
3 years ago
5

Four students measured the same line with a ruler like the one shown below. The results were as follows: 5.52 cm, 6.63 cm, 5.5,

and 5.93. Even though you cannot see the line they actually measured, which of the recorded measurements are possible valid measurements for this instrument, according to its precision? Select all that apply. 1. 5.52 2. 6.63 3. 5.5 4. 5.93
Physics
1 answer:
finlep [7]3 years ago
6 0

Answer:

correct answer is 1 and 3

Explanation:

In direct measurement with an instrument, the precision or absolute error of the instrument is given by its appreciation, in this case we see that the measurements have two decimal places, so the appreciation of the instrument must be 0.01 cm

Based on this appreciation, the valid measurements are 5.52 and 5.5.

the other two measurements have errors much higher than the assessment of the instrument, for which there must have been some errors in the measurement.

The correct answer is 1 and 3

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A small piece of Styrofoam packing material is dropped from a height of 2.60 m above the ground. Until it reaches terminal speed
Vadim26 [7]

Answer:

Explanation:

a ) After the attainment of terminal speed , object takes 4.5 s to cover a distance of 2 m

So terminal speed V = 2 / 4.5

= .444 m /s

When it attains terminal speed , acceleration becomes zero

0 = g - B x .444

B = 22.25 s⁻¹

b ) At t = 0 , v = 0

a = g - B v

a = g at t = 0

c ) When v = .15

a = g - 22.25 x .15

= 9.8 - 3.31

= 6.5  m /s²

7 0
4 years ago
Two rocks of different masses are rolling down a hill at the same speed. Which rock (small one or big one) would have more kinet
aivan3 [116]

Answer:

Kinetic energy of bigger rock will be more than that of smaller one.

Explanation:

Kinetic energy of the rock is given by,

Kinetic energy = \frac{1}{2} m v^{2}

As velocity of both the rocks are same. Thus, kinetic energy is directly proportional to the mass of the rock

Kinetic energy ∝ mass

So, For greater mass kinetic energy will be greater and for smaller mass kinetic energy will be smaller.

Hence, Kinetic energy of bigger rock will be more than that of smaller one.

3 0
3 years ago
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Gli iceberg nel Nord Atlantico rappresentano un rischio per la navigazione, costringendo ad allungare le rotte di navigazione di
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I DONT UNDERSTND IS ANOTHER LANGUAGR

6 0
3 years ago
A 3.00 μF capacitor is charged to 480 V and a 4.00 μF capacitor is charged to 500 V . Part A These capacitors are then disconnec
pogonyaev

Q before connected = Q after connected C1V1+C2V2 = (C1+C2) V

C1= 3×10^-6 F

V1= 480v

C2= 4×10^-6 F

V2= 500v

(3×10^-6)×(480) + (4×10^-6)×(500) = (3×10^-6 + 4×10^-6) × V

Simplifying the above, we get:

( 1440× 10^-6) + (2000 ×10^-6) = (7 × 10^-6) × V.

Further simplified as:

3440 × 10^-6 = 7 × 10^-6 × V

Making V the subject

V = 491.43volts

Therefore the potential difference across each capacitor is 491.43v

4 0
3 years ago
John drives a distance of 90 Km to the right at a steady speed of V1=25.00 m/s. Then he stops at the gas station for 10 minutes.
aleksley [76]

a. Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

b. t=6000\ s is the total time taken in the trip

c. d=126000\ m is the total distance

d. s=54000\ m towards right from the starting point.

e. v_a=21\ m.s^{-1}

f. \vec v_a=9\ m.s^{-1} towards right.

Explanation:

a.

Speed is a scalar quantity while velocity is a vector quantity.

Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

Speed is a directionless quantity while velocity constitutes direction.

b.

<em>Total time of round trip when we're given:</em>

  • distance travelled to the right, d_r=90000\ m
  • speed while travelling to the right, v_r=25\ m.s^{-1}
  • time spent at gas station, t_g=600\ s
  • time spent while travelling back towards the left, t_l=30\times 60=1800\ s
  • speed while travelling to the left, v_{_l}=20\ m.s^{-1}

<em>Now time taken for travelling towards right:</em>

t_r=\frac{d_r}{v_r}

t_r=\frac{90000}{25}

t_r=3600\ s

<u>Therefore total time taken in the round trip:</u>

t=t_r+t_l+t_g

t=3600+600+1800

t=6000\ s

c.

<em>Now, distance travelled towards left:</em>

d_l=v_{_l}\times t_l

d_l=20\times1800

d_l=36000\ m

<u>Therefore total distance:</u>

d=d_l+d_r

d=36000+90000

d=126000\ m

d.

Now, total displacement:

s=d_r-d_l

s=90000-36000

s=54000\ m towards right from the starting point.

e.

<u>Average speed:</u>

v_a=\frac{d}{t}

v_a=\frac{126000}{6000}

v_a=21\ m.s^{-1}

f.

<u>Average velocity:</u>

\vec v_a=\frac{s}{t}

\vec v_a=\frac{54000}{6000}

\vec v_a=9\ m.s^{-1} towards right.

4 0
3 years ago
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