First, we have a change in the velocity from 85 to 164 m/s in 10 sec.
Then, we calculate the <u>acceleration </u>as:
Hence we need to calculate the velocity of the space vehicle at t = 2 sec using the first equation of motion:
Then, using the second equation of motion to calculate the distance:
Supposedly there is life on Mars but it’s early to say for sure
<span>there is no horizontal displacement if he went straight up
straight up means vertical, so his vertical displacment is 20 m</span>
The forward force you exert on the fish and your backward action will allow you to reach the shore.
<h3>
Newton's third law of motion</h3>
Newton's third law of motion states that for every action, there is an equal and opposite reaction.
Fa = -Fb
Let's assume the fish is held in the hook, this will give you the opportunity to throw the fish forward while still holding it.
When the the fish is thrown forward, you will move backwards with an equal force based on Newton's third law. Your backward momentum towards the shore will help to maintain equal linear momentum between you and the fish.
Thus, this forward force of the fish and your backward action will allow you to reach the shore.
Learn more Newton's third law of motion here: brainly.com/question/25998091
Answer:
The magnitude of the applied torque is
(e) is correct option.
Explanation:
Given that,
Mass of object = 3 kg
Radius of gyration = 0.2 m
Angular acceleration = 0.5 rad/s²
We need to calculate the applied torque
Using formula of torque
Here, I = mk²
Put the value into the formula
Hence, The magnitude of the applied torque is